Question

[Rinney Sun]

Tính :

D=\(\frac{4^7x2^8}{3x2^{15}x16^2+5x2^2x\left(2^{10}\right)^2}\)

Answer 1

[Lê Tài Bảo Châu]

\(D=\frac{4^7.2^8}{3.2^{15}.16^2+5.2.\left(2^{10}\right)^2}\)

\(=\frac{2^{14}.2^8}{3.2^{15}.2^8+5.2.2^{20}}\)

\(=\frac{2^{22}}{3.2^{23}+5.2^{21}}\)

\(=\frac{2^{22}}{2^{21}.\left(2^2.3+5\right)}\)

\(=\frac{2}{2^2.3+5}\)

\(=\frac{2}{17}\)

Answer 2

[Nguyễn Linh Chi]

\(D=\frac{\left(2^2\right)^7.2^8}{3.2^{15}.\left(2^4\right)^2+5.2^2.2^{20}}\)

\(=\frac{2^{14}.2^8}{3.2^{15}.2^8+5.2^{22}}\)

\(=\frac{2^{22}}{3.2^{23}+5.2^{22}}\)

\(=\frac{2^{22}}{2^{22}\left(3.2+5\right)}=\frac{1}{11}\)