\(\frac{25.\left(-2\right)^{11}-2^{12}.10}{2^4.3^2.40}\)
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![](https://rs.olm.vn/images/avt/0.png?1311)
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\(\frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6.2^{12}.3^5}\)- \(\frac{5^{10}.7^3-5^{10}.7^4}{5^9.7^3+5^9.7^3.2^3}\)= \(\frac{2^{12}.3^4.\left(3-1\right)}{2^{24}.3^{11}}\)-\(\frac{5^{10}.7^3.\left(1-7\right)}{5^9.7^3.\left(1+8\right)}\)=\(\frac{1}{2^{11}.3^7}\)-\(\frac{-10}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
TA có\(\frac{2^{12}.3^5.4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3}\)
=\(\frac{2^{12}.3^5.2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}-\frac{5^{10}.7^3-5^{10}.7^4}{5^9.7^3}\)
=\(\frac{2^{24}.3^9}{2^{12}.3^5.\left(3+1\right)}-\frac{5^{10}.7^3.\left(1-7\right)}{5^9.7^3}\)
=\(2^{20}.3^4-30\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Gợi ý : Phân tích hết ra thành tích các thừa số nguyên tố rồi đặt cái chung ra ngoài
-> rút gọn
-> kết quả
P/S : bài này cx ko dài lắm nhưg lười ^^
![](https://rs.olm.vn/images/avt/0.png?1311)
\(B=\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
\(=\frac{2^{12}.3^5-2^{12}.3^6}{2^{12}.3^6+2^{12}.3^5}-\frac{5^{10}.7^3-5^{10}.7^4}{5^9.7^3+5^9.2^3.7^3}\)
\(=\frac{2^{12}.3^5.\left(1-3\right)}{2^{12}.3^6.\left(3+1\right)}-\frac{5^9.7^3.\left(1-7\right)}{5^9.7^3\left(1+2^3.1\right)}\)
\(=\frac{-1}{2}-\frac{-2}{3}=\frac{-7}{6}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}=\frac{2^{12}.3^5-\left(2^2\right)^6.\left(3^2\right)^2}{2^{12}.3^6+\left(2^3\right)^4.3^5}-\frac{5^{10}.7^3-\left(5^2\right)^5.\left(7^2\right)^2}{\left(5^3.7\right)^3+5^9.2^3.7^3}\)
\(=\frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}-\frac{5^{10}.7^3-5^{10}.7^4}{5^9.7^3+5^9.2^3.7^3}=\frac{2^{12}.3^4\left(3-1\right)}{2^{12}.3^5\left(3+1\right)}-\frac{5^{10}.7^3\left(1-7\right)}{5^9.7^3\left(1+2^3\right)}=\frac{2}{3.4}-\frac{5.\left(-6\right)}{9}\)
\(=\frac{1}{6}-\frac{-10}{3}=\frac{1}{6}-\frac{-20}{6}=\frac{21}{6}=\frac{7}{2}\)
Lẽ ra là làm xong cho bạn rồi, vậy mà tự nhiên máy sập, giờ chép lại, oải quá :|
\(\frac{25.\left(-2\right)^{11}-2^{12}.10}{2^4.3^2.40}\) = \(\frac{5^2.\left(2\right)^{11}-2^{11}.2.10}{2^4.3^2.40}\)= \(\frac{\left(2\right)^{11}.\left(5^2-2.10\right)}{2^4.3^2.40}\)=\(\frac{\left(2\right)^{11-4=7}.\left(5^2-2.10\right)}{3^2.40}\)=\(\frac{\left(2\right)^7.\left(5\right)}{3^2.5.8}\)=\(\frac{\left(2\right)^7}{3^2.2^3}\)=\(\frac{\left(2\right)^{7-3}}{3^2}\)=\(\frac{16}{9}\)