(7×13+8×13):(9/2/3-y)=39
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a) y - 6 chia 2 - ( 48 - 24 x 2 chia 6 - 3 ) = 0
=> y - 6 chia 2 - ( 48 - 48 chia 6 - 3 ) = 0
=> y - 6 chia 2 - ( 48 - 8 -3 ) = 0
= > y - 6 chia 2 - 37 = 0
=> y - 6 chia 2 = 0 + 37
=> y - 6 chia 2 = 37
=> y -6 = 37 chia 2
=> y - 6 = 37 / 2
=> y = 37 / 2 + 6
=> y = 49 / 2
Vậy y = 49 / 2
b) ( 7 x 13 + 8 x 13 ) chia ( 92 /3-y ) = 39
=> ( 91 + 104 ) chia ( 92/3 - y ) =39
=> 195 chia ( 92 /3 - y ) = 39
=> 92/3 - y = 7605
=> y = 7605 + 92/3
=> y = 22907 /3
Vậy y = 22907 / 3
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{7.13+8.13}{9\dfrac{2}{3}-y}=39\)
=> \(\dfrac{13.\left(7+8\right)}{\dfrac{29}{3}-y}=39\)
=> \(\dfrac{13.15}{\dfrac{29}{3}-y}=39\)
=> \(\dfrac{195}{\dfrac{29}{3}-y}=39\)
=> \(\dfrac{29}{3}-y=5\)
=> y = \(\dfrac{14}{3}\)
@Bùi Thị Phương Anh
\(\dfrac{7.13+8.13}{9\dfrac{2}{3}-y}=39\)
\(\Leftrightarrow\dfrac{13\left(7+8\right)}{\dfrac{29}{3}-y}=39\)
\(\Leftrightarrow\dfrac{13.15}{\dfrac{29}{3}-y}=39\)
\(\Leftrightarrow\dfrac{195}{\dfrac{29}{3}-y}=39\)
\(\Leftrightarrow\dfrac{29}{3}-y=39\)
\(\Leftrightarrow y=\dfrac{14}{3}\)
Vậy ....
![](https://rs.olm.vn/images/avt/0.png?1311)
Dấu \(.\)là dấu nhân
\(\left(7.13+8.13\right):\left(9\frac{2}{3}-y\right)=39\)
\(\Rightarrow13.\left(7+8\right):\left(\frac{29}{3}-y\right)=39\)
\(\Rightarrow13.15:\left(\frac{29}{3}-y\right)=39\)
\(\Rightarrow195:\left(\frac{29}{3}-y\right)=39\)
\(\Rightarrow\frac{29}{3}-y=195:39\)
\(\Rightarrow\frac{29}{3}-y=5\)
\(\Rightarrow y=\frac{29}{3}-5\)
\(\Rightarrow y=\frac{29}{3}-\frac{15}{3}\)
\(\Rightarrow y=\frac{14}{3}\)
Vậy \(y=\frac{14}{3}\)
~ Ủng hộ nhé .
P/s : Đúng nha
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left[7\times13+8\times13\right]:\left[9\frac{2}{3}-y\right]=39\)
\(\left[\left(7+8\right)\times13\right]:\left[\frac{29}{3}-y\right]=39\)
\(\left[15\times13\right]:\left[\frac{29}{3}-y\right]=39\)
\(195:\left[\frac{29}{3}-y\right]=39\)
\(\frac{29}{3}-y=195:30\)
\(\frac{29}{3}-y=\frac{13}{2}\)
\(y=\frac{29}{3}-\frac{13}{2}\)
\(y=\frac{19}{6}\)
Học tốt #
[ 7 x 13 + 8 x 13 ] : [ \(9\frac{2}{3}\) - y ] = 39
[ 13 x ( 7 + 8 )] : [ \(9\frac{2}{3}\)- y ] = 39
[ 13 x 15 ] : [\(9\frac{2}{3}\) - y ] = 39
195 : [\(\frac{29}{3}\) - y ] = 39
[ \(\frac{29}{3}\) - y ] = 195 : 39 (*1 )
[\(\frac{29}{3}-y\)] = 5
y = \(\frac{29}{3}-5\)
y = \(\frac{14}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(y-6:2-\left(48-24.2:6-3\right)=0.\)
\(\Rightarrow y-3-\left(48-8-3\right)=0\)
\(\Rightarrow y-3-37=0\)
\(\Rightarrow y=0+37+3=40\)
Vậy y = 40
b) \(\left(7.13+8.13\right):\left(9\frac{2}{3}-y\right)=39\)
\(\Rightarrow195:\left(\frac{29}{3}-y\right)=39\)
\(\Rightarrow\frac{29}{3}-y=195:39=5\)
\(\Rightarrow y=\frac{29}{3}-5=\frac{14}{3}\)
Vậy y=\(\frac{14}{3}\)
a) y - 6 : 2 - ( 48 - 24 x 2 : 6 - 3 ) = 0
y - 6 : 2 - ( 48 - 48 : 6 - 3 ) = 0
y - 6 : 2 - ( 48 - 8 - 3 ) = 0
y - 6 : 2 - 37 = 0
y - 3 = 0 + 37
y - 3 = 37
y = 37 + 3
y = 40
b) ( 7 x 13 + 8 x 13 ) : ( \(9\frac{2}{3}\) - y ) = 39
( 15 x 13 ) : ( \(9\frac{2}{3}\) - y ) = 39
195 : ( \(9\frac{2}{3}\) - y ) = 39
\(9\frac{2}{3}\) - y = 195 : 39
\(9\frac{2}{3}-y=5\)
\(y=9\frac{2}{3}-5\)
\(y=\frac{14}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`@` `\text {Ans}`
`\downarrow`
`1,`
`a)`
`-7/25 + (-8)/25`
`= (-7 - 8)/25`
`= -15/25`
`= -3/5`
`b)`
`6/13 + (-15)/39`
`= 18/39 + (-15)/39`
`= (18 - 15)/39`
`= 3/39`
`= 1/13`
`c)`
`5/7 + 4/(-14)`
`= 10/14 + (-4)/14`
`= (10 - 4)/14`
`= 6/14`
`= 3/7`
`d)`
`-8/18 + (-15)/27`
`= -4/9 + (-5)/9`
`= (-4-5)/9`
`= -9/9 = -1`
`2,`
`a)`
`3/5 + (-7)/4`
`= 12/20 + (-35)/20`
`= (12 - 35)/20`
`=-23/20`
`b)`
`(-2) + (-5)/8`
`= (-16)/8 + (-5)/8`
`= (-16 - 5)/8`
`= -21/8`
`c)`
`1/8 + (-5)/9`
`= 9/72 + (-40)/72`
`= (9-40)/72`
`= -31/72`
`d)`
`6/13 + (-14)/39`
`= 18/39 + (-14)/39`
`= (18 - 14)/39`
`= 4/39`
`e)`
`(-18)/24 + 15/21`
`= (-3)/4 + 5/7`
`= (-21)/28 + 20/28`
`= (-21 + 20)/28`
`= -1/28`
dấu ghạch chéo là j
là chia