26-x/995+22-x/197+18-x/199=12-x/334
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LH
0
27 tháng 4 2019
\(\frac{26-x}{995}\)+2+\(\frac{22-x}{997}\)+\(\frac{18-x}{999}\)+2=\(\frac{12-x}{334}\)+6
\(\frac{2016-x}{995.2}\)+\(\frac{2016-x}{997.2}\)+\(\frac{2016-x}{999.2}\)-\(\frac{2016-x}{334.6}\)=0
(2016-x)(\(\frac{1}{995.2}\)+\(\frac{1}{997.2}\)\(\frac{1}{999.2}\)-\(\frac{1}{334.6}\))=0
Dễ thấy giá trị biểu thức trong ngoặc thứ 2 khác 0
Nên 2016-x=0=>x=2016
Vậy giá trị của x là 2016
22 tháng 2 2022
Câu 1:
a: =(1+2-3-4)+(5+6-7-8)+...+(2013+2014-2015-2016)
=(-4)+(-4)+...+(-4)
=-4x504=-2016
b: \(B=\dfrac{3}{4}\cdot\dfrac{8}{9}\cdot...\cdot\dfrac{195}{196}=\dfrac{1\cdot3\cdot2\cdot4\cdot...\cdot13\cdot15}{2\cdot3\cdot...\cdot14\cdot2\cdot3\cdot...\cdot14}=\dfrac{15}{14\cdot2}=\dfrac{15}{28}\)
WK
0
CT
0
NL
1
21 tháng 8 2017
Bài 3:
\(a,\dfrac{x-1}{10}+\dfrac{x-1}{11}=\dfrac{x-1}{12}+\dfrac{x-1}{13}\)
\(\Rightarrow\dfrac{x-1}{10}+\dfrac{x-1}{11}-\dfrac{x-1}{12}-\dfrac{x-1}{13}=0\)
\(\Rightarrow\left(x-1\right)\left(\dfrac{1}{10}+\dfrac{1}{11}-\dfrac{1}{12}-\dfrac{1}{13}\right)=0\)
Mà \(\dfrac{1}{10}+\dfrac{1}{11}-\dfrac{1}{12}-\dfrac{1}{13}\ne0\)
\(\Rightarrow x-1=0\Rightarrow x=1\)
Vậy x = 1
b, \(\dfrac{x-2000}{10}+\dfrac{x-1999}{9}=\dfrac{x-1998}{8}+\dfrac{x-1997}{7}\)
\(\Rightarrow\dfrac{x-2000}{10}+1+\dfrac{x-1999}{9}+1=\dfrac{x-1998}{8}+\dfrac{x-1997}{7}+1\)
\(\Rightarrow\dfrac{x-1990}{10}+\dfrac{x-1990}{9}-\dfrac{x-1990}{8}-\dfrac{x-1990}{7}=0\)
\(\Rightarrow\left(x-1990\right)\left(\dfrac{1}{10}+\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{7}\right)=0\)
Mà \(\dfrac{1}{10}+\dfrac{1}{9}-\dfrac{1}{8}-\dfrac{1}{7}\ne0\)
\(\Rightarrow x-1990=0\Rightarrow x=1990\)
MD
1
MT
19 tháng 11 2015
\(\frac{25-x}{995}+\frac{21-x}{997}+\frac{17-x}{999}=\frac{11-x}{334}\)
\(\Rightarrow\frac{25-x}{995}+2+\frac{21-x}{997}+\frac{17-x}{999}+2=\frac{11-x}{334}+6\)
\(\Rightarrow\frac{25-x}{995}+\frac{1990}{995}+\frac{21-x}{997}+\frac{1994}{997}+\frac{17-x}{999}+\frac{1998}{999}=\frac{11-x}{334}+\frac{2004}{334}\)
\(\Rightarrow\frac{2015-x}{995}+\frac{2015-x}{997}+\frac{2015-x}{999}=\frac{2015-x}{334}\)
\(\Rightarrow\frac{2015-x}{995}+\frac{2015-x}{997}+\frac{2015-x}{999}-\frac{2015-x}{334}=0\)
\(\Rightarrow\left(2015-x\right)\left(\frac{1}{995}+\frac{1}{997}+\frac{1}{999}+\frac{1}{334}\right)=0\)
\(\Rightarrow2015-x=0\left(\text{vì }\frac{1}{995}+\frac{1}{997}+\frac{1}{999}+\frac{1}{334}\ne0\right)\)
\(\Rightarrow x=2015\)