Question

[Kim Tuyền]

log_a⁴ X - log_a² X +log_aX=\(\frac{3}{4}\) với 0<a khác 1

Answer 1

[Nguyễn Việt Lâm]

ĐKXĐ: \(x>0\)

\(log_{a^4}x-log_{a^2}x+log_ax=\frac{3}{4}\)

\(\Leftrightarrow\frac{1}{4}log_ax-\frac{1}{2}log_ax+log_ax=\frac{3}{4}\)

\(\Leftrightarrow\frac{3}{4}log_ax=\frac{3}{4}\)

\(\Leftrightarrow log_ax=1\)

\(\Rightarrow x=a\)