Question

[Trân Khơi My]

bài 1: tính hợp lí

 A = \(\frac{1}{3}\). \(\frac{-6}{13}\) . \(\frac{-9}{10}\) . \(\frac{-13}{36}\)

B = \(\frac{-5}{12}\) .  \(\frac{4}{19}\)+ \(\frac{-7}{12}\) . \(\frac{4}{19}\) - \(\frac{40}{57}\)

C = \(\frac{3}{7}\) . \(\frac{9}{26}\) - \(\frac{1}{14}\) . \(\frac{1}{13}\) - \(\frac{1}{7}\)

D = \(\frac{1}{3}\) . \(\frac{4}{5}\) + \(\frac{1}{3}\) . \(\frac{6}{5}\) + \(\frac{2}{3}\)

Ai làm nhanh mình tik, giải rõ giúp mình, mình đang cần gấp, cảm ơn

Answer 1

[Đặng Viết Thái]

\(A=\frac{1}{3}.\frac{-9}{10}.\frac{-6}{13}.\frac{-13}{36}=\frac{-3}{10}.\frac{-1}{6}=\frac{1}{20}\)

\(B=\frac{4}{19}\left(\frac{-5}{12}+\frac{-7}{12}\right)-\frac{40}{57}=\frac{-4}{19}-\frac{40}{57}=\frac{-52}{57}\)

2 câu còn lại tự làm

Answer 2

[bin]

\(A=\frac{1}{3}.\frac{-6}{13}.\frac{-9}{10}.\frac{-13}{36}\)

\(A=\frac{1}{1}.\frac{-2}{13}.\frac{-9}{10}.\frac{-13}{36}\)

\(A=\frac{-2}{13}.\frac{-9}{10}.\frac{-13}{36}\)

\(A=\frac{-1}{13}.\frac{-9}{5}.\frac{-13}{36}\)

\(A=\frac{-1}{13}.\frac{-1}{5}.\frac{-13}{4}\)

\(A=\frac{-13}{260}=\frac{-1}{20}\)