tìmx biết
\(\left(\frac{3x}{7}\left|+1\right|\right):\left(-1\right)=\frac{-1}{28}\)
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12 tháng 10 2016
\(\left(2\frac{1}{3}+3\frac{1}{2}\right):\left(x+3\frac{1}{7}\right)+7\frac{1}{2}=1\frac{69}{86}\)
\(\left(\frac{7}{3}+\frac{7}{2}\right):\left(x+\frac{22}{7}\right)+\frac{15}{2}=\frac{155}{86}\)
\(\left(\frac{14}{6}+\frac{21}{6}\right):\left(x+\frac{22}{7}\right)+\frac{15}{2}=\frac{155}{86}\)
\(\frac{35}{6}:\left(x+\frac{22}{7}\right)=\frac{155}{86}-\frac{15}{2}\)
\(\frac{35}{6}:\left(x+\frac{22}{7}\right)=\frac{155}{86}-\frac{645}{86}\)
\(\frac{35}{6}:\left(x+\frac{22}{7}\right)=\frac{-245}{43}\)
\(x+\frac{22}{7}=\frac{35}{6}:\frac{-245}{43}=\frac{35}{6}\cdot\frac{-43}{245}\)
\(x+\frac{22}{7}=\frac{-43}{42}\)
\(x=\frac{-43}{42}-\frac{22}{7}=\frac{-43}{42}-\frac{132}{42}\)
\(x=\frac{-25}{6}\)
DD
0
HT
3
30 tháng 4 2017
\(\left(\frac{3x}{7}+1\right)=\frac{-1}{28}.\left(-4\right)\)
\(\left(\frac{3x}{7}+1\right)=\frac{1}{7}\)
\(\frac{3x}{7}=\frac{1}{7}-1\)
\(\frac{3x}{7}=\frac{-6}{7}\)
=> 3x = -6
=> x = -6 : 3
=> x = -2
Vậy x = -2
30 tháng 4 2017
\(\left(\frac{3x}{7}+1\right)=\frac{-1}{28}.\left(-4\right)\)
\(\left(\frac{3x}{7}+1\right)=\frac{1}{7}\)
\(\frac{3x}{7}=\frac{1}{7}-1=\frac{-6}{7}\)
\(3x=-6\)
\(=>x=\left(-6\right):3=-2\)
LT
3
S
18 tháng 3 2017
\(\left(\frac{3x}{7}+1\right)\div\left(-4\right)=\frac{-1}{28}\)
\(\frac{3x}{7}+1=\frac{-1}{28}\times\left(-4\right)\)
\(\frac{3x}{7}+1=\frac{1}{7}\)
\(\frac{3x}{7}=\frac{1}{7}-1\)
\(\frac{3x}{7}=\frac{-6}{7}\)
\(3x=\frac{-6}{7}\times7\)
\(3x=-6\)
\(x=-2\)
Vậy x = -2
tớ ko bít đúng hay sai đâu nha
18 tháng 3 2017
\(\Leftrightarrow\)\(-\frac{1}{28}\cdot\left(-4\right)\)=\(\frac{3x}{7}+1\)
\(\Leftrightarrow\frac{1}{7}=\frac{3x}{7}+1\)
\(\Leftrightarrow\frac{1}{7}-1=3x:7\)
\(\Leftrightarrow3x:7=-\frac{6}{7}\)
\(\Leftrightarrow3x=\frac{-6}{7}.7\)
\(\Leftrightarrow x=-6:3\)
\(\Leftrightarrow x=-2\)
Chú ý : \(\left|+1\right|\)cũng vẫn là bằng 1
Ta có : \((\frac{3x}{7}\cdot1):(-1)=\frac{-1}{28}\)
\(\Rightarrow(\frac{3x}{7}\cdot1)=\frac{-1}{28}\cdot(-1)\)
\(\Rightarrow(\frac{3x}{7}\cdot1)=\frac{1}{28}\)
\(\Rightarrow\frac{3x}{7}=\frac{1}{28}:1\)
\(\Rightarrow\frac{3x}{7}=\frac{1}{28}\)
\(\Rightarrow3x=\frac{1}{28}\cdot7\)
\(\Rightarrow3x=\frac{1}{4}\)
\(\Rightarrow x=\frac{1}{4}\div3\)
\(\Rightarrow x=\frac{1}{12}\)