a)| 4.x - 7 | = 13
b)| 1-2.x| =9
c) ( x^2 + 5).( x^2 - 36)
d) ( 2.x -1 ).(y+3)=11
e) ( 5-2.x ).(2.y+1)=13
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7 tháng 10 2021
Bài 1:
a) \(=\dfrac{8}{15}\left(\dfrac{7}{13}+\dfrac{6}{13}\right)=\dfrac{8}{15}.1=\dfrac{8}{15}\)
b) \(=\dfrac{3.3-7-2.4}{12}=-\dfrac{6}{12}=-\dfrac{1}{2}\)
Bài 2:
\(\dfrac{x}{2,7}=-\dfrac{2}{3,6}\Rightarrow x=\dfrac{\left(-2\right).2,7}{3,6}\Rightarrow x=-\dfrac{3}{2}\)
Bài 3:
\(\dfrac{x}{2}=\dfrac{y}{5}=\dfrac{x+y}{2+5}=-\dfrac{21}{7}=-3\)
\(\Rightarrow\left\{{}\begin{matrix}x=\left(-3\right).2=-6\\y=\left(-3\right).5=-10\end{matrix}\right.\)
LN
1 tháng 11 2015
a\(\left(x-3\right)^2-\left(x+2\right)^2-5\left(\frac{1}{5}-7\right)=-30\)
=>(x-3-x-2)(x-3+x+2)-x+35=-30
=>-5(2x-1)-x+35=-30
=>-10x+5-x+35=-30
=>-11x+40=-30
=>-11x=-70 =>x=70/11
d)\(\left(x+3\right)^2-\left(x+5\right)\left(x-5\right)=2\)
\(=>\left(x+3\right)^2-x^2+25=2\)
\(=>\left(z+3-z\right)\left(z+3+z\right)+25=2\)
\(=>3\left(2z+3\right)+25-2=0\)
\(=>6z+9+23=0\)
\(=>6x+32=0=>6x=-32=>x=-\frac{16}{3}\)
e)\(3\left(x+2\right)^2+\left(2x-1\right)^2-7\left(x+3\right)\left(x-3\right)=36\)
\(=>3\left(x^2+4x+4\right)+\left(4x^2-4x+1\right)-7\left(x^2-9\right)=36\)
\(=>3x^2+12x+12+4x^2-4x+1-7x^2+63\)
\(=>8x+76=36=>8x=36-76=>x=-40\div8=-5\)
g)\(\left(x-1\right)\left(x^2+x+1\right)-x\left(x+2\right)\left(x-2\right)=5\)
\(=>x^3-1-x\left(x^2-4\right)=5=>x^3-1-x^3+4x=5\)
\(=>4x-1=5=>4x=6=>x=\frac{3}{2}\)
2 tháng 8 2021
a) \(\dfrac{2}{5}+\dfrac{11}{15}=\dfrac{6}{15}+\dfrac{11}{15}=\dfrac{17}{15}\)
b) \(\dfrac{7}{8}-\dfrac{7}{9}=\dfrac{63}{72}-\dfrac{56}{72}=\dfrac{7}{72}\)
c) \(\dfrac{11}{13}\cdot\dfrac{26}{31}=\dfrac{26}{13}\cdot\dfrac{11}{31}=\dfrac{22}{31}\)
d) \(\dfrac{1}{2}:\dfrac{1}{3}\cdot\dfrac{2}{5}=\dfrac{1}{2}\cdot3\cdot\dfrac{2}{5}=\dfrac{3}{5}\)
2 tháng 3 2022
\(a)x=\dfrac{1}{4}+\dfrac{5}{13}=\dfrac{33}{52}.\\ b)\dfrac{x}{3}=\dfrac{2}{3}+\dfrac{-1}{7}.\\ \Leftrightarrow\dfrac{x}{3}=\dfrac{11}{21}.\\ \Leftrightarrow\dfrac{7x}{21}=\dfrac{11}{21}.\\ \Rightarrow7x=11.\\ \Leftrightarrow x=\dfrac{11}{7}.\\ c)\dfrac{x}{3}=\dfrac{16}{24}+\dfrac{24}{36}=\dfrac{2}{3}+\dfrac{2}{3}=\dfrac{4}{3}.\\ \Rightarrow x=4.\\ d)\dfrac{x}{15}=\dfrac{1}{5}+\dfrac{2}{3}=\dfrac{13}{15}.\\ \Rightarrow x=13.\)
a) |4x - 7| = 13
=> \(\orbr{\begin{cases}4x-7=13\\4x-7=-13\end{cases}}\)
=> \(\orbr{\begin{cases}4x=20\\4x=-6\end{cases}}\)
=> \(\orbr{\begin{cases}x=5\\x=-\frac{3}{2}\end{cases}}\)
b) tương tự)
d) Ta có: 11 = 1. 11 = 11. 1
Lập bảng:
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e) tương tự