Biết rằng ƯCLN của 2 số tự nhiên bằng 4, số bé bằng 8. Tìm số lớn
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ML
0
LP
1
3 tháng 11 2016
Gọi số lớn là a (a thuộc N, a> 8)
Ta có 8 = 2^3. ƯCLN(8;a) = 2^2 nên a có dạng 2^2 x p với p là một số có ước nguyên tố. VD : p = 3; 5; 9; ......
JK
7
24 tháng 11 2016
Gọi số lớn là a=4k (k∈N). Do số nhỏ là 8 = 4. 2 nên k>2 và (k,2)=1. Vậyk=2n+1 (n=1,2,3,...) do đó số lớn có dạng 4(2n+1).
LP
0
8 tháng 12 2015
a) goi hai so la a ; b va a >b
vi UCLN(a,b)=18=>a=18k ; b=18q (trong do UCLN (k,q)=1 va k>q)
=>a+b=162
18k+18q =162
18(k+q)=162
k+q=9
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29 tháng 10 2016
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52542000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 | 542454550212.100000000000000000000000000000000000000000000000000000000000000000000000000000 |
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