1 .2 . 3 + 2 . 3 .4 + 3 . 4. 5 +....... + 48 . 49 .50
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
So sánh tổng : S = 1/5 + 1/9 + 1/10 + 1/41 + 1/42 với 1/2
S=
=50/50+50/49+50/48+...+50/2
=50.(1/50+1/49+1/48+...+1/4+1/3+1/2)
=50
P=
P=(1/49+1)+(2/48+1)+...+(48/2+1)+1
P= 50/49+50/48+....+50/2+50/50=1
vậy s/p = 1/50
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{2}{2\cdot3\cdot4}+\frac{2}{3\cdot4\cdot5}+...+\frac{2}{47\cdot48\cdot49}+\frac{2}{48\cdot49\cdot50}\)
\(A=\frac{1}{2\cdot3}-\frac{1}{3\cdot4}+\frac{1}{3\cdot4}-\frac{1}{4\cdot5}+...+\frac{1}{47\cdot48}-\frac{1}{48\cdot49}+\frac{1}{48\cdot49}-\frac{1}{49\cdot50}\)
\(A=\frac{1}{2\cdot3}-\frac{1}{49\cdot50}\)
\(A=\frac{1}{6}-\frac{1}{2450}\)
\(A=\frac{611}{3675}\)
mong giúp đc bn.thk cho mk
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ax2=1x2/1x2x3+1x2/2x3x4+...+1x2/48x49x50
Ax2=1/1x2-1/2x3+1/2x3-1/3x4+...+1/48x49-1/49x50
Ax2=1/1x2-1/49x50
Ax2=1/2-1/2450
Ax2=1225/2450-1/2450
Ax2=1224/2450
A=1224/2450:2
A=1224/2450X1/2
A=1224/4900
A=306/1225
![](https://rs.olm.vn/images/avt/0.png?1311)
A = 1 × 2 × 3 + 2 × 3 × 4 + .....+ 48 × 49 × 50
ta có 4 x A = 1 x 2 x 3 x 4 + 2 x 3 x 4 x (5 -1) + .....+ 48 × 49 × 50 x (51 - 47)
= 1 x 2 x 3 x 4 + 2 x 3 x 4 x 5 - 1 x 2 x 3 x 4 + ... + 48 x 49 x 50 x 51 - 47 x 48 x 49 x 50
= 48 x 49 x 50 x 51
suy ra A = (48 x 49 x 50 x 51) : 4
= 12 x 49 x 50 x 51
nhớ k cho mik nha rùi mik lm nốt cho
![](https://rs.olm.vn/images/avt/0.png?1311)
Đặt A = 1.2.3 + 2.3.4 + 3.4.5 + ... + 48.49.50
4A = 1.2.3.4 + 2.3.4.4 + 3.4.5.4 + ... + 48.49.50.4
4A = 1.2.3.4 + 2.3.4.(5 - 1) + 3.4.5.(6 - 2) + ... + 48.49.50.(51 - 47)
4A = 1.2.3.4 + 2.3.4.5 - 1.2.3.4 + 3.4.5.6 - 2.3.4.5 + ... + 48.49.50.51 - 47.48.49.50
4A = 48.49.50.51
A = 48.49.50.51 : 4
A = 1499400
1.2.3 + 2.3.4 + 3.4.5 + ... + 48.49.50
Đặt A = 1.2.3 + 2.3.4 + 3.4.5 + ... + 48.49.50
4A = 1.2.3.4 + 2.3.4.4 + 3.4.5.4 + ... + 48.49.50.4
4A = 1.2.3.4 + 2.3.4.(5-1) + 3.4.5.(6-2) + ... + 48.49.50.(51-47)
4A = 1.2.3.4 + 2.3.4.5 - 1.2.3.4 + 3.4.5.6 - 2.3.4.5 + ... + 48.49.50.51 - 47.48.49.50
4A = ( 1.2.3.4 + 2.3.4.5 + 3.4.5.6 + ... + 48.49.50.51 ) - ( 1.2.3.4 - 2.3.4.5 - 47.48.49.50 )
4A = \(\frac{48.49.50.51}{4}\)
A = 1499400