(- 2008). .57 + 1004 . (-86)/ 32 . 74 + 16 . (-48)
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b: \(C=75\left(2-128+128\right)=75\cdot2=150\)
e: \(E=\dfrac{1}{5}\left(\dfrac{5}{4\cdot9}+\dfrac{5}{9\cdot14}+...+\dfrac{5}{69\cdot74}\right)\)
\(=\dfrac{1}{5}\left(\dfrac{1}{4}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{14}+...+\dfrac{1}{69}-\dfrac{1}{74}\right)\)
\(=\dfrac{1}{5}\cdot\dfrac{70}{74}=\dfrac{14}{74}=\dfrac{7}{37}\)
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\(D=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot...\cdot\frac{2017}{2018}\)
\(D=\frac{1}{2018}\)
Vậy \(D=\frac{1}{2018}\)
\(E=\frac{1}{4.9}+\frac{1}{9.14}+\frac{1}{14.19}+...+\frac{1}{64.69}+\frac{1}{69.74}\)
\(E=\frac{1}{5}\cdot\left(\frac{1}{4}-\frac{1}{9}+\frac{1}{9}-\frac{1}{14}+...+\frac{1}{69}-\frac{1}{74}\right)\)
\(E=\frac{1}{5}\cdot\left(\frac{1}{4}-\frac{1}{74}\right)\)
\(E=\frac{1}{5}\cdot\frac{35}{148}=\frac{7}{148}\)
Vậy E = ...
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a) -2008.57 + 1004.(-86)
= -2.1004.57 + 1004.(-86)
= 1004.(-114) + 1004.(-86)
= 1004.(-114 - 86)
= 1004.(-200)
= -200800.
b) 32.74 + 16.(-48)
= 2.16.74 + 16.(-48)
= 148.16 + 16.(-48)
= 16.(148 - 48)
= 16.100
= 1600.
-2008,57 + 1004.(-86)
=1004.(-2).57 + 1004.(-86)
=1004.[(-2).57 + (-86)]
=1004.(-200)
=-200800
32.74 + 16.(-48)
=16.148 + 16.(-48)
=16.[148 + (-48)]
=16.100
=1600
![](https://rs.olm.vn/images/avt/0.png?1311)
(-31).13+(-91).5+131+(-5)+9
= (-403)+(-455)+(-5)+9
= -863+9
=-854
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