\(\left(\frac{11}{5}\div\frac{3}{19}\times\frac{2}{31}\right)\div\frac{-5}{19}\)
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LM
1
25 tháng 3 2017
a) = -3/7 . 5/11 + -3/7 . 6/11 + 9/7
= -3/7. ( 5/11 + 6/11 ) + 9/7
= -3/7. 1 + 9/7
= -3/7 + 9/7
= 6/7
b) = 4/13 + 9/13 + -11/5 + 6/5 - 3/4
= 13/13 + -5/5 - 3/4
= 1 + (-1) - 3/4
= 0 - 3/4
= -3/4
c) = -19/17. 4/7 + 19/17. -3/7 + 19/17
= 19/17. -4/7 + 19/17. -3/7 + 19/17.1
= 19/17.( -4/7 + -3/7 + 19/17
= 19/17. -7/7 + 19/17
= 19/17. (-1) + 19/17
= -19/17 + 19/17
= 0
tk mk nha,thanks
11 tháng 7 2019
1) ( \(\frac{55}{3}\): 15 + \(\frac{26}{3}\) . \(\frac{7}{2}\)) : [(\(\frac{37}{3}\) + \(\frac{62}{7}\)) . \(\frac{7}{18}\)] : \(\frac{-1704}{445}\)
= ( \(\frac{55}{3}\). \(\frac{1}{15}\) + \(\frac{91}{3}\)) : [ \(\frac{445}{21}\) . \(\frac{7}{18}\)] . \(\frac{-445}{1704}\)
= ( \(\frac{11}{9}\)+ \(\frac{91}{3}\)) : \(\frac{445}{54}\). \(\frac{-445}{1704}\) = \(\frac{284}{9}\). \(\frac{54}{445}\). \(\frac{-445}{1704}\)= \(\frac{284}{9}\). (\(\frac{54}{445}\). \(\frac{-445}{1704}\))
= \(\frac{284}{8}\). \(\frac{-9}{284}\)
= \(\frac{-9}{8}\)
DT
1
NH
19 tháng 3 2023
`12/19xx19/18+11/15:11/5`
`=2/3+11/15xx5/11`
`=2/3+1/3`
`=3/3`
`=1`
EG
17 tháng 8 2018
\(=\frac{11}{-5}\cdot\frac{-9}{11}\cdot\frac{15}{-14}\cdot\frac{2}{5}+-\frac{2}{77}\cdot\frac{5}{-3}\)
\(=\frac{9}{5}\cdot-\frac{15}{14}\cdot\frac{2}{5}+\frac{10}{231}\)
\(=-\frac{841}{1155}\)
\(\left(\frac{11}{5}:\frac{3}{19}\cdot\frac{2}{31}\right):\frac{-5}{19}\)
\(=\left(\frac{11\cdot19\cdot2}{5\cdot3\cdot31}\right)\cdot\frac{-19}{5}\)
\(=\frac{418\cdot\left(-19\right)}{465\cdot5}\)
\(=\frac{-7942}{2325}\)
\(\left(\frac{11}{5}:\frac{3}{19}\cdot\frac{2}{31}\right)\cdot\frac{-5}{19}\)
\(=\left(\frac{11}{5}\cdot\frac{19}{3}\cdot\frac{2}{31}\right)\cdot\frac{-19}{5}\)
\(=\frac{11\cdot19\cdot2\cdot\left(-19\right)}{5\cdot3\cdot31\cdot5}\)
\(=-\frac{7942}{2325}\)