37^2 + 2.37.13+13^2
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
áp dụng hằng đẳng thức là đc nha .
37^2 + 2.37.13 + 13^2
= ( 37 + 13 ) ^2
= 50^2
= 2500
chúc bn hk tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(29.31=\left(30-1\right)\left(30+1\right)=30^2-1=900-1=899\)
b) \(33,3^2-2.33,3.3,3+3,3^2=\left(33,3-3,3\right)^2=30^2=900\)
c) \(20,1.19,9=\left(20+0,1\right)\left(20-0,1\right)=20^2-0,1^2=400-0.01=399,99\)
d) \(37^2+2.37.13+13^2=\left(37+13\right)^2=50^2=2500\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(37^2+2\cdot37\cdot13+13^2\)
\(=1369+962+169\)
\(=2500\)
b) \(35^2+24^2-48\cdot35\)
\(=125+576-1680\)
\(=121\)
c) sai quy luật
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : (x + 4)2 - (x + 1)(x - 1) = 16
<=> x2 + 8x + 16 - (x2 - 1) = 16
<=> x2 + 8x + 16 - x2 + 1 = 16
<=> 8x + 17 = 16
=> 8x = -1
=> x = \(-\frac{1}{8}\)
Ta có : x2 - 4x + 4 =0
<=> x2 - 2.x.2 + 22 = 0
<=> (x - 2)2 = 0
=> x - 2 = 0
=> x = 2
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(27^2+13^2+2.37.13=\left(27+13\right)^2\)
b, \(87^2+57^2-174.67=\left(87-57\right)^2\)
c, \(x^2-2xy+2y^2+2y+1\)
\(=\left(x^2-2xy+y^2\right)+\left(y^2+2y+1\right)\)
\(=\left(x-y\right)^2+\left(y+1\right)^2\)
d, \(4x^2-12x-y^2+2y+1\)
\(=4\left(x^2-3x\right)-\left(y^2-2y+1\right)+2\)
\(=4\left(x^2-\dfrac{3}{2}.x.2+\dfrac{9}{4}-\dfrac{9}{4}\right)-\left(y-1\right)^2+2\)
\(=\left(x-\dfrac{3}{2}\right)^2-\left(y-1\right)^2-7\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(37^2+2.37.13+13^2\\ =\left(37+13\right)^2=50^2=2500\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1, ( 37 . 13 - 13 . 1 ) : ( 24 + 37 . 12 )
[ 13 . ( 37 - 1 ) ] : ( 12 . 2 + 37 . 12 )
( 13 . 36 ) : [ 12 ( 2 + 37 ) ]
( 13 . 36 ) : ( 12 . 36 )
36
chắc z ^^
lm bừa ko cần mt
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: \(37^2+2\cdot37\cdot13+13^2\)
\(=\left(37+13\right)^2=50^2=2500\)
b) Ta có: \(201^2=\left(200+1\right)^2\)
\(=200^2+2\cdot200+1\)
\(=40000+200+1=40201\)
c) Ta có: \(37\cdot43=\left(40+3\right)\cdot\left(40-3\right)\)
\(=40^2-3^2=1600-9=1591\)
\(37^2+2\times37+13^2.\)
\(=37\times37+2\times37+13^2\)
\(=37\times\left(37+2\right)+13^2\)
\(=37\times39+13^2\)
\(=37\times39+169\)
\(=1443+169=1612\)
\(37^2+2.37.13+13^2=\left(37+13\right)^2=2500\)