Bài 1:Tìm nghiệm
a)f(x)=3(x-1)-4
b)g(x)=2(x-1)+3(x+2)
c)h(x)=4x2+4x-1
d)k(x)=\(\dfrac{x-1}{2}\) +\(\dfrac{x-2}{3}\)+1
Bài2:tìm x, y, z
a) \(\dfrac{x}{2}\)=\(\dfrac{y}{3}\)=\(\dfrac{z}{-4}\) và x+y+z =-5
b)\(\dfrac{x}{3}\)=\(\dfrac{y}{2}\)=;\(\dfrac{y}{3}\)=\(\dfrac{z}{5}\) và x+y-2z=11
c)\(\dfrac{x+1}{2}\)=\(\dfrac{y-2}{3}\)=\(\dfrac{z+3}{4}\) và...
Đọc tiếp
Bài 1:Tìm nghiệm
a)f(x)=3(x-1)-4
b)g(x)=2(x-1)+3(x+2)
c)h(x)=4x2+4x-1
d)k(x)=\(\dfrac{x-1}{2}\) +\(\dfrac{x-2}{3}\)+1
Bài2:tìm x, y, z
a) \(\dfrac{x}{2}\)=\(\dfrac{y}{3}\)=\(\dfrac{z}{-4}\) và x+y+z =-5
b)\(\dfrac{x}{3}\)=\(\dfrac{y}{2}\)=;\(\dfrac{y}{3}\)=\(\dfrac{z}{5}\) và x+y-2z=11
c)\(\dfrac{x+1}{2}\)=\(\dfrac{y-2}{3}\)=\(\dfrac{z+3}{4}\) và x+2y-z=-30
Bài 1:
a: =>3x-3-4=0
=>3x=7
hay x=7/3
b: =>2x-2+3x+6=0
=>5x+4=0
hay x=-4/5
c: =>\(4x^2+4x-1=0\)
hay \(x\in\left\{\dfrac{-1+\sqrt{2}}{2};\dfrac{-1-\sqrt{2}}{2}\right\}\)
d: \(\Leftrightarrow3x-3+2x-4+6=0\)
=>5x+1=0
hay x=-1/5