Tính bằng cách hợp lí : \(\dfrac{2.6^9-2^5.18^4}{2^2.6^8}\)
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TT
2
MV
28 tháng 10 2017
\(\dfrac{2\cdot6^9-2^5\cdot18^4}{2^2\cdot6^8}\\ =\dfrac{2\cdot\left(2\cdot3\right)^9-2^5\cdot\left(2\cdot3^2\right)^4}{2^2\cdot\left(2\cdot3\right)^8}\\ =\dfrac{2\cdot2^9\cdot3^9-2^5\cdot2^4\cdot3^8}{2^2\cdot2^8\cdot3^8}\\ =\dfrac{2^9\cdot3^8\left(2\cdot3-1\right)}{2^{10}\cdot3^8}\\ =\dfrac{5}{2}\)
HM
3
22 tháng 10 2019
\(\frac{2.6^9.2^5.18^4}{2^2.6^8}=\frac{2.\left(2.3\right)^9.2^5.\left(2.3^2\right)^4}{2^2.\left(2.3\right)^8}=\frac{2.2^9.3^9.2^5.2^4.3^8}{2^2.2^8.3^8}=\frac{2^{19}.3^{17}}{2^{10}.3^8}=2^9.3^9\)
\(=\left(2.3\right)^9=6^9\)
22 tháng 10 2019
Tính hợp lý
\(\frac{2.6^9.2^5.18^4}{2^2.6^8}=\frac{2^6.2^9.3^9.2^4.3^8}{2^2.2^8.3^8}=\frac{2^{19}.3^{17}}{2^{10}.3^8}=2^9.3^9=6^9\)
học tốt nhé bn
#Tịnh
27 tháng 11 2016
\(\frac{2.6^9-2^5.18^4}{2^6.6^8}=\frac{2^{10}.3^9-2^9.3^8}{2^{14}.3^8}=\frac{2^9.3^8.\left(6-1\right)}{2^{14}.3^8}=\frac{5}{2^5}=\frac{5}{32}\)
LH
27 tháng 11 2016
= 2.29.39-25.24.34.34/ 26.38.28
=210.39-29.38/ 214.38
=29.38.(2.3-1.1)/214.38
=5/32
L
0
19 tháng 3 2021
\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}:\sqrt{\dfrac{25}{9}}=\dfrac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}:\dfrac{5}{3}\)
\(=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}.\dfrac{5}{3}=\dfrac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1-5\right)}.\dfrac{5}{3}=\dfrac{1-3}{1-5}.\dfrac{5}{3}=\dfrac{1}{2}.\dfrac{5}{3}=\dfrac{5}{6}\)
19 tháng 3 2021
\(\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\div\sqrt{\dfrac{25}{9}}\)
\(=\dfrac{2^{10}\cdot3^8-2\cdot2^9\cdot3^9}{2^{10}\cdot3^8+2^8\cdot3^8\cdot2^2\cdot5}\div\dfrac{5}{4}\)
=\(\dfrac{2^{10}\cdot3^8\left(1-2\cdot3\right)}{2^{10}\cdot3^8\left(1+5\right)}\div\dfrac{5}{4}\)
=\(\dfrac{1-6}{1+5}\cdot\dfrac{4}{5}\)
=\(-\dfrac{5}{6}\cdot\dfrac{4}{5}\)
=\(-\dfrac{2}{3}\)
20 tháng 9 2021
\(A=\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)
\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+3^8\cdot2^{10}\cdot5}\)
\(=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\cdot\left(1+5\right)}\)
\(=-\dfrac{2}{6}=-\dfrac{1}{3}\)
20 tháng 10 2023
d: \(\left(2^2:\dfrac{4}{3}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17\)
\(=\left(4\cdot\dfrac{3}{4}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17\)
\(=\left(3-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17\)
\(=\dfrac{5}{6}\cdot\dfrac{6}{5}-17=1-17=-16\)
h: \(\dfrac{\left(-1\right)^3}{15}+\left(-\dfrac{2}{3}\right)^2:2\dfrac{2}{3}-\left|-\dfrac{5}{6}\right|\)
\(=-\dfrac{1}{15}+\dfrac{-8}{27}:\dfrac{8}{3}-\dfrac{5}{6}\)
\(=-\dfrac{1}{15}-\dfrac{1}{9}-\dfrac{5}{6}\)
\(=\dfrac{-6-10-75}{90}=\dfrac{-91}{90}\)
k: \(\dfrac{2\cdot6^9-2^5\cdot18^4}{2^2\cdot6^8}\)
\(=\dfrac{2^{10}\cdot3^9-2^5\cdot2^4\cdot3^8}{2^2\cdot2^8\cdot3^8}\)
\(=\dfrac{2^{10}\cdot3^9-2^9\cdot3^8}{2^{10}\cdot3^8}=\dfrac{2^9\cdot3^8\left(2\cdot3-1\right)}{2^{10}\cdot3^8}\)
\(=\dfrac{5}{2}\)
n: \(3-\left(-\dfrac{7}{8}\right)^0+\left(\dfrac{1}{2}\right)^3\cdot16\)
\(=3-1+\dfrac{1}{8}\cdot16\)
=2+2
=4
Ta có:\(\dfrac{2.6^9-2^5.18^4}{2^2.6^8}=\dfrac{2^{10}.3^9-2^9.3^8}{2^{10}.3^8}=\dfrac{2^9.3^8.\left(2.3-1\right)}{2^{10}.3^8}=\dfrac{2^9.3^8.5}{2^{10}.3^8}=\dfrac{5}{2}\)