ai giup vs ak
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\(.5^{x-3}-2.5^2=3.5^2\)
\(5^{x-3}=25\)
Ta có :
\(5^2=25\)
=> x-3 = 2
=> x=5
5x-3-2.52=3.52
5x-3=3.52+2.52
5x-3=52.(3+2)
5x-3=52.5
5x-3=53
=>x-3=3
x=6
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\(x\left(2-y\right)-y+2-2=5\)
\(\left(2-y\right)\left(x+1\right)=7\)
⇒ (x+1) và (2-y) ϵ {-1;1;-7;7}
⇒ (x;y) ϵ {(-2;5);(0;-5);(-8;3);(6;1)}
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1.Mai always gets up early and does exercise in the morning.
2, He bought some books to read at home.
3.She sometimes help her mother cook dinner
4.Mai was happy at the party.
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\(\left(5-2x\right)^2-16=0\)
\(\Leftrightarrow\left(5-2x\right)^2-4^2=0\)
\(\Rightarrow\left(5-2x-4\right)\left(5-2x+4\right)=0\)
\(\Rightarrow\orbr{\begin{cases}5-2x-4=0\\5-2x+4=0\end{cases}\Leftrightarrow\orbr{\begin{cases}-2x=4-5\\-2x=-4-5\end{cases}}\Leftrightarrow\orbr{\begin{cases}-2x=-1\\-2x=-9\end{cases}}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{-1}{-2}=\frac{1}{2}\\x=\frac{-9}{-2}=\frac{9}{2}\end{cases}}\)
Vậy ................................
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\(3\left(x-1\right)^2-3x\left(x-5\right)=1\)
\(\Leftrightarrow\)\(3x^2-6x+3-3x^2+15x=1\)
\(\Leftrightarrow\)\(9x=-2\)
\(\Leftrightarrow\)\(x=-\frac{2}{9}\)
Vậy...
\(x^2-2x+1=25\)
\(\Leftrightarrow\)\(x^2-2x-24=0\)
\(\Leftrightarrow\)\(\left(x+4\right)\left(x-6\right)=0\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x+4=0\\x-6=0\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=-4\\x=6\end{cases}}\)
Vậy...
ai giải zùm cau 2 ,3