Question

[Phan Đức Gia Linh]

@Phan Đức Gia Linh _ Xin cảm ơn những bạn đã quan tâm tới câu hỏi của mình!

Tìm x, biết:

1) \(\dfrac{2}{x+1}\) = \(\dfrac{x+1}{8}\)

2) \(\dfrac{23+x}{40-x}\)

3) \(\dfrac{x-4}{x-7}\) = \(\left(\dfrac{-3}{5}\right)^2\)

4) \(\dfrac{3+x}{7+y}\) = \(\dfrac{3}{7}\) và x + y = 20

5) \(\dfrac{x}{x+1}\) > 0

6) \(\dfrac{2x-1}{2-x}\) \(\le\) 0

Các bạn cố gắng giải đầy đủ giúp mình!

Answer 1

[Mysterious Person]

1) \(\dfrac{2}{x+1}=\dfrac{x+1}{8}\Leftrightarrow\left(x+1\right)\left(x+1\right)=2.8\Leftrightarrow\left(x+1\right)^2=16\)

\(\Leftrightarrow\left\{{}\begin{matrix}x+1=4\\x+1=-4\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\) vậy \(x=3;x=-5\)

2) thiếu quế phải nha

3) \(\dfrac{x-4}{x-7}=\left(\dfrac{-3}{5}\right)^2\Leftrightarrow\dfrac{x-4}{x-7}=\dfrac{9}{25}\Leftrightarrow9.\left(x-7\right)=25.\left(x-4\right)\)

\(\Leftrightarrow9x-63=25x-100\Leftrightarrow25x-9x=-63+100\)

\(\Leftrightarrow16x=37\Leftrightarrow x=\dfrac{37}{16}\) vậy \(x=\dfrac{37}{16}\)

4) ta có : \(x+y=20\Leftrightarrow y=20-x\)

\(\dfrac{3+x}{7+y}=\dfrac{3}{7}\Leftrightarrow7\left(3+x\right)=3\left(7+y\right)\Leftrightarrow21+7x=21+3y\)

\(\Leftrightarrow7x=3y\Leftrightarrow7x-3y=0\Leftrightarrow7x-3\left(20-x\right)=0\)

\(\Leftrightarrow7x-60+3x=0\Leftrightarrow10x=60\Leftrightarrow x=6\)

\(\Rightarrow6+y=20\Leftrightarrow y=14\) vậy \(x=6;y=14\)

Answer 2

[Mysterious Person]

\(\dfrac{23+x}{40-x}=\dfrac{-3}{4}\Leftrightarrow4\left(23+x\right)=-3\left(40-x\right)\)

\(\Leftrightarrow92+4x=-120+3x\Leftrightarrow4x-3x=-120-92\)

\(\Leftrightarrow x=-212\) vậy \(x=-212\)