Question

[I LOVE KOOKIE]

b2 : tìm x, biết :

a) 1 / (x + 1). (x + 2) + 1 / (x + 2). (x + 3) + 1 / (x + 3). (x + 4) + ... + 1 / (x + 1999). (x + 2000) = 1 / x + 200 = 1/5

( chú ý : / là phần nha )

Answer 1

[Mashiro Shiina]

\(\dfrac{1}{\left(x+1\right)\left(x+2\right)}+\dfrac{1}{\left(x+2\right)\left(x+3\right)}+\dfrac{1}{\left(x+3\right)\left(x+4\right)}+...+\dfrac{1}{\left(x+1999\right)\left(x+2000\right)}=\dfrac{1}{x+200}=\dfrac{1}{5}\)\(\Rightarrow\dfrac{1}{x+1}-\dfrac{1}{x+2}+\dfrac{1}{x+2}-\dfrac{1}{x+3}+\dfrac{1}{x+3}-\dfrac{1}{x+4}+...+\dfrac{1}{x+1999}-\dfrac{1}{x-2000}=\dfrac{1}{x+200}=\dfrac{1}{5}\)

\(\Rightarrow\dfrac{1}{x+1}-\dfrac{1}{x+2000}=\dfrac{1}{x+200}=\dfrac{1}{5}\)

Đề này sai nhé,hình như thừa dữ kiện đề r