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10 tháng 7 2017

UNREAL CONDITION

1) If my father was here now, he could help you.

2) If the children went to the circus, they would see the performing animals.

3) If the buses weren't full up, they would stop.

4) If I were good at English, I could read this book.

5) If he wasn't tired, he could score a goal.

6) If they were at home today, they would meet their aunt.

7) If Peter didn't drink too much coffee, he could sleep.

8) If the weather was nice today, we would go to the zoo.

9) If the boy had some books, he could write that composition better.

10) If I knew his address, I could visit him.

11) If we had a bicycle, we could go there for a picnic.

12) If tickets weren't expensive, we would visit Hanoi.

TENSES AFTER WISH

1) I wish the referee were fair.

2) They wish the water wasn't polluted.

3) I wish I knew German and Spanish.

4) They wish they had a sightseeing ride about London.

5) I wish they would come with us.

6) I wish she wouldn't leave for France next month.

7) I wish you could come to the party.

8) I wish we had a torch.

9) I wish I didn't have to work today.

10) I wish I wouldn't have to work tomorrow.

PTHH: \(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)

Ta có: \(\left\{{}\begin{matrix}m_{H_2SO_4}=588\cdot5\%=29,4\left(g\right)\Rightarrow n_{H_2SO_4}=\dfrac{29,4}{98}=0,3\left(mol\right)\\n_{Al_2O_3}=\dfrac{20,4}{102}=0,2\left(mol\right)\end{matrix}\right.\)

Xét tỉ lệ: \(\dfrac{0,2}{1}>\dfrac{0,3}{3}\) \(\Rightarrow\) Al2O3 còn dư

\(\Rightarrow n_{Al_2\left(SO_4\right)_3}=0,1\left(mol\right)=n_{Al_2O_3\left(dư\right)}\)

\(\Rightarrow C\%_{Al_2\left(SO_4\right)_3}=\dfrac{0,1\cdot342}{20,4+588-0,1\cdot102}\cdot100\%\approx5,72\%\)

21 tháng 10 2021

\(d,ĐK:x\ge1\\ PT\Leftrightarrow\sqrt{x-1}=2+\sqrt{x+1}\\ \Leftrightarrow x-1=2+x+1+4\sqrt{x+1}\\ \Leftrightarrow4\sqrt{x+1}=-4\Leftrightarrow x\in\varnothing\left(4\sqrt{x+1}\ge0\right)\\ g,ĐK:x\ge\dfrac{1}{2}\\ PT\Leftrightarrow x+\sqrt{2x-1}+x-\sqrt{2x-1}+2\sqrt{\left(x+\sqrt{2x-1}\right)\left(x-\sqrt{2x-1}\right)}=2\\ \Leftrightarrow2x+2\sqrt{x^2-2x+1}=2\\ \Leftrightarrow\sqrt{\left(x-1\right)^2}=\dfrac{2-2x}{2}=1-x\\ \Leftrightarrow\left|x-1\right|=1-x\\ \Leftrightarrow\left[{}\begin{matrix}x-1=1-x\left(x\ge1\right)\\x-1=x-1\left(x< 1\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\left(tm\right)\\x\in R\end{matrix}\right.\)

 

10 tháng 7 2017

Câu I bạn đã đăng,mk làm r nhé.

LINK: Câu hỏi của Nguyễn Quỳnh Như - Tiếng anh lớp 9 | Học trực tuyến

II) ADJ

1:Excited

2:Interesting

3:Developed

4:Fascinating

5:Fascinated

6:Boring ; Bored

7:Healthy

8:Beautiful

9:Worried

10:Boring

11:Exciting

12:Successful

13:Competitive

14:Good

15:Excited

16:Amazed

17:Happy.

~GOOK LUCK~

24 tháng 12 2021

Bài 2: 

a: \(\Leftrightarrow4x^2-20x+25-4x^2+12x=0\)

=>-8x=-25

hay x=25/8

1. 

a) x (x - 5) + (x + 3)(x - 3)=

= x^2 - 5x + (x + 3)(x - 3)

= x^2 - 5x + x^2 - 9

= x^2 + x^2 - 5x - 9

= 2x^2 - 5x - 9.

b. không thể nhìn thấy hết bài được. Nó bị mất dấu!!

c. (20x^2 + 7x - 6) : (5x - 2)

= (5x - 2) (4x + 3) : (5x - 2)

= 4x + 3.

2. 

a. (2x - 5)^2 - 4x (x - 3)= 0

                       -8x + 25= 0

                -8x + 25 - 25= 0 - 25

                               -8x= -25

                          -8x : 8= -25 : 8

                                 x = 25/8

Vậy x= 25/8

b. 2(x - 5) - x^2 - 5x= 0

                        -10x= 0

              -10x : (-10)= 0 : (-10)

                              x= 0

Vậy x= 0

c. Lí do cũng giống câu b bài 1.

2 tháng 12 2021

Bài 3.

Định luật ll Niu-tơn:

\(\overrightarrow{F}+\overrightarrow{F_{ms}}=m\cdot\overrightarrow{a}\)

\(\Rightarrow F-F_{ms}=m\cdot a\)

Gia tốc vật:

\(a=\dfrac{F-F_{ms}}{m}=\dfrac{4,5-\mu mg}{m}=\dfrac{4,5-0,2\cdot1,5\cdot10}{1,5}=1\)m/s2

Vận tốc vật sau 2s:

\(v=a\cdot t=1\cdot2=2\)m/s

Câu 1: A
Câu 2: B

Câu 3: D
Câu 4: A

Câu 5: C

Câu 6: B

Câu 7: A

Câu 9: B

 

26 tháng 11 2021

\(A=x^2-4xy+4y^2+2x-4y+1+y^2+2y+1+2008\)

\(A=\left(x-2y\right)^2+2\left(x-2y\right)+1+\left(y+1\right)^2+2008\)

\(A=\left(x-2y+1\right)^2+\left(y+1\right)^2+2008\ge2008\)

\(\Rightarrow A_{min}=2008\Leftrightarrow\left\{{}\begin{matrix}x-2y+1=0\\y+1=0\end{matrix}\right.\)\(\Leftrightarrow\left\{{}\begin{matrix}x=-3\\y=-1\end{matrix}\right.\)

26 tháng 11 2021

mình cảm ơn ạ.

17 tháng 12 2022

a) điện trở tương đương của đoạn mạch

R = R1 + R2 =10 + 20= 30 (Ω)

Cường độ dòng điện chạy qua đoạn mạch

I = \(\dfrac{U}{Rtđ}=\dfrac{6}{30}=0,2\left(A\right)\)

17 tháng 12 2022

b) vì R1 nối tiếp R2  nên ta có:

I= I1= I2 = I3= 0,2 (A)

-> U1= I1 . R1 = 0,2 .10 = 2 (V)

-> U2 = I2 . R2 = 0,2. 20 = 4 (V)