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a) (-5) . (-4) + (-5) . 14 = (-5 ) . [ (-4) + 14 ] = -50
b ) 3 . ( 5 + 8 ) = 13 . ( -3 ) + 13 . 8 = 65
a) (-2)+ (-5) = -7
Vì: -7< -5
=> (-2)+ (-5) < -7
b) (-3)+ (-8)= -11
Vì: (-10) > (-11)
=> -10> (-3)+ (-8)
a) (- 16) . (- 7) . 5 = [(- 16) . 5] . (- 7) = 560.
b) 11 . (- 12) + 11 . (- 18) = 11 . [(- 12) + (- 18)] = 11 . [- (12 + 18)] = 11 . (- 30) = - 330.
c) 87 . (- 19) – 37 . (- 19) = (- 19) . (87 – 37) = (- 19) . 50 = - 950.
d) 41 . 81 . (- 451) . 0 = 0.
a, \(\left(-6\right)+\left(-3\right).....\left(-6\right)\)
\(\left(-9\right)< \left(-6\right)\)
Vậy \(\left(-6\right)+\left(-3\right)< \left(-6\right)\)
b,\(\left(-9\right)+\left(-12\right)....\left(-20\right)\)
\(\left(-21\right)< \left(-20\right)\)
\(\Rightarrow\left(-9\right)+\left(-12\right)< \left(-20\right)\)
a)
\(5+\left(-7\right)+9+\left(-11\right)+13+\left(-15\right)\)
\(=\left[5+\left(-7\right)\right]+\left[9+\left(-11\right)\right]+\left[13+\left(-15\right)\right]\)
\(=\left(-2\right)+\left(-2\right)+\left(-2\right)=-6\)
b)
\(\left(-6\right)+8+\left(-10\right)+12+\left(-14\right)+16\)
\(=\left[\left(-6\right)+8\right]+\left[\left(-10\right)+12\right]+\left[\left(-14\right)+16\right]\)
\(=2+2+2=6\)
a: \(A=\dfrac{7}{12}+\dfrac{5}{72}-\dfrac{11}{36}=\dfrac{42}{72}+\dfrac{5}{72}-\dfrac{22}{72}=\dfrac{25}{72}\)
b: \(B=\dfrac{8+5}{10}:\dfrac{-5}{13}=\dfrac{13}{10}\cdot\dfrac{13}{-5}=-\dfrac{169}{100}\)
c: \(C=\left(\dfrac{88}{132}-\dfrac{33}{132}+\dfrac{60}{132}\right):\left(\dfrac{55}{132}+\dfrac{132}{132}-\dfrac{84}{132}\right)\)
\(=\dfrac{88-33+60}{55+132-84}=\dfrac{115}{103}\)
a)( -11) .(8.9)= (-11) .8 - (-11) .9= 11
b) (-12).10 - (-9) . 10= [ -12 - (-9) ] . 10 = -30
a) \(\left(-11\right)\cdot\left(8-9\right)=\left(-11\right)\cdot8-\left(-11\right)\cdot9=11\)
b) \(\left(-12\right)\cdot10-\left(-9\right)\cdot10=\left[-12-\left(-9\right)\right]\cdot10=-30\)