Question

[Phương Socola Nguyên]

cho m<n, so sánh:

\(\dfrac{m}{2}-5\) và \(\dfrac{n}{2}-5\)

tìm số tự nhiên n thỏa mãn:

a, 5(2-3n)+42+3n ≥ 0

b, \(\left(n+1\right)^2-\left(n+2\right)\left(n-2\right)\le1,5\)

Answer 1

[Trần Thị Thu Ngân]

1, giải : Vì m<n (gt)\(\Rightarrow\)\(\dfrac{m}{2}< \dfrac{n}{2}\)\(\Rightarrow\)\(\dfrac{m}{2}-5< \dfrac{n}{2}-5\)

2. a, 5(2-3n)+42+3n \(\ge\) 0

\(\Leftrightarrow\) 10-15n +42+3n\(\ge\) 0

\(\Leftrightarrow\) 52-12n\(\ge\) 0

\(\Leftrightarrow\) -12n \(\ge\) -52

\(\Leftrightarrow\)n\(\le\)\(\dfrac{13}{3}\)

b, \(\left(n+1\right)^2-\left(n-2\right)\left(n+2\right)\le15\)

\(\Leftrightarrow n^2+2n+1-n^2+4\le1,5\)

\(\Leftrightarrow2n+5\le1,5\)

\(\Leftrightarrow n\le-1,75\)