Tính nhanh nếu có thể:
-5/7x2/11-5/11x9/7-2/5/7
Giúp mình với!!!Khẩn cấp đấy!!!
K
Khách
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Những câu hỏi liên quan
28 tháng 7 2015
a) (137x25-25x37):10
=25x(137-37):10
=25x100:10
=2500:10
=250
b) 2/7x21/4-2/7:13/4
=2/7x21/4-2/7x4/13
=2/7x(21/4-4/13)
=2/7x257/52
=257/182
c)(124x237+152):(870+235x122)
=(29388+152):(870+28670)
=29540:29540
=1
28 tháng 7 2015
a) (137 x 25 - 25 x 37 ) : 10 = (25 x (137 - 37) ) : 10
= (25 x 100) : 10
= 2500 : 10
= 250
28 tháng 7 2015
a)=(3425-925):10
=25200:10
=250
b)=3/2-8/91
=257/182
c)=(29388+152):(870+28670)
=29540:29540
=1
d)=1161+1539/72
=2700/72=75/2
e)=10/77+45/77x9/7
=10/77+405/539
=475/539
li ke cho mình nha Lam Le thi
O
9 tháng 5 2022
a) \(\dfrac{7}{30}+\dfrac{\left(-12\right)}{37}+\dfrac{23}{30}+\dfrac{\left(-25\right)}{37}=\left(\dfrac{7}{30}+\dfrac{23}{30}\right)+\left(\dfrac{-12}{37}+\dfrac{-25}{37}\right)=1+\left(-1\right)=0\)
b) \(\dfrac{5}{7}\cdot\dfrac{5}{11}+\dfrac{5}{7}\cdot\dfrac{2}{11}-\dfrac{5}{7}\cdot\dfrac{14}{11}=\dfrac{5}{7}\cdot\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)=\dfrac{5}{7}\cdot\left(-\dfrac{7}{11}\right)=-\dfrac{5}{11}\)
c) \(\dfrac{\left(-5\right)}{7}\cdot\dfrac{3}{13}-\dfrac{5}{7}\cdot\dfrac{10}{13}+1\dfrac{5}{7}=\dfrac{5}{7}\cdot\dfrac{-3}{13}-\dfrac{5}{7}\cdot\dfrac{10}{13}+\dfrac{12}{7}=\dfrac{5}{7}\cdot\left(\dfrac{-3}{13}-\dfrac{10}{13}\right)+\dfrac{12}{7}=\dfrac{5}{7}\cdot\left(-1\right)+\dfrac{12}{7}=\left(-\dfrac{5}{7}\right)+\dfrac{12}{7}=\dfrac{7}{7}=1\)
T
5 tháng 5 2019
#)Trả lời :
a) \(\frac{-1}{2}+\frac{2}{7}-\frac{5}{28}\)
\(=\frac{-3}{14}-\frac{5}{28}\)
\(=\frac{-11}{28}\)
b) \(5\frac{3}{4}+\left(\frac{1}{9}-1\frac{3}{4}\right)\)
\(=\left(5\frac{3}{4}-1\frac{3}{4}\right)+\frac{1}{9}\)
\(=4+\frac{1}{9}\)
\(=4\frac{1}{9}=\frac{37}{9}\)
c) \(\frac{-5}{7}x\frac{2}{11}+\frac{-5}{7}x\frac{9}{11}+3\frac{5}{7}\)
\(=\frac{-5}{7}x\left(\frac{2}{11}+\frac{9}{11}\right)+3\frac{5}{7}\)
\(=\frac{-5}{7}x1+3\frac{5}{7}\)
\(=\frac{-5}{7}+3\frac{5}{7}\)
\(=\frac{-5}{7}+\frac{26}{7}\)
\(=\frac{21}{7}=3\)
#~Will~be~Pens~#
K
2
17 tháng 7 2019
(6:3/5-7/6×6/7) : (21/5×10/11+57/11)
=(10-1):(42/11+57/11)
=9:9
=1
DP
17 tháng 7 2019
(6:3/5-7/6x6/7):(21/5x10/11+57/11)
= (10-1):(42/11+57/11)
=9:9
=1
~~~~ Hoc tot ~~~~~
20 tháng 9 2017
a) 2 + 4 + 6 + ... + 100
\(=\frac{\left[\left(100-2\right):2+1\right].\left(100+2\right)}{2}=2550\)
b) 1 + 3 + 7 + ... + 99
\(=\frac{\left[\left(99-1\right):2+1\right].\left(99+1\right)}{2}=2500\)
c) 1 + 5 + 9 + 13 + ... + 49
\(=\frac{\left[\left(49-1\right):4+1\right].\left(49+1\right)}{2}=325\)
AT
12 tháng 6 2017
\(\dfrac{2}{7}\cdot\dfrac{2}{11}+\dfrac{5}{7}\cdot\dfrac{12}{11}-\dfrac{5}{7}\cdot\dfrac{7}{11}\)
\(=\dfrac{4}{77}+\dfrac{5}{7}\left(\dfrac{12}{11}-\dfrac{7}{11}\right)\)
\(=\dfrac{4}{77}+\dfrac{5}{7}\cdot\dfrac{5}{11}=\dfrac{4}{77}+\dfrac{25}{77}=\dfrac{29}{77}\)
p/s: toán 6
\(\dfrac{-5}{7}.\dfrac{2}{11}-\dfrac{5}{11}.\dfrac{9}{7}-2\dfrac{5}{7}\)
\(=\dfrac{-2}{7}.\dfrac{5}{11}-\dfrac{5}{11}.\dfrac{9}{7}-\dfrac{19}{7}\)
\(=\dfrac{5}{11}.\left(\dfrac{-2}{7}-\dfrac{9}{7}\right)-\dfrac{19}{7}\)
\(=\dfrac{5}{11}.\dfrac{-11}{7}-\dfrac{19}{7}\)
\(=\dfrac{-5}{7}-\dfrac{19}{7}\)
\(=\dfrac{-24}{7}\)
\(\dfrac{-5}{7}.\dfrac{2}{11}-\dfrac{5}{11}.\dfrac{9}{7}-2\dfrac{5}{7}\)
\(=\dfrac{-2}{7}.\dfrac{5}{11}-\dfrac{5}{11}.\dfrac{9}{7}-\dfrac{19}{7}\)
\(=\dfrac{5}{7}\left(\dfrac{-2}{7}-\dfrac{9}{7}\right)-\dfrac{19}{7}\)
\(=\dfrac{5}{7}.\dfrac{-11}{7}-\dfrac{19}{7}\)
\(=\dfrac{5.\left(-11\right)}{11.7}-\dfrac{19}{7}\)
\(=\dfrac{-5.11}{11.7}-\dfrac{19}{7}\)
\(=\dfrac{-5}{7}-\dfrac{19}{7}\)
\(=\dfrac{-5-19}{7}\)
\(=\dfrac{\left(-5\right)+\left(-19\right)}{7}\)
\(=\dfrac{-24}{7}\)