tính \(\dfrac{^{7.12^8.5^4-6^9.20^4}}{6^{10}.10^5-7.3^9.80^4}\)
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VV
1
LT
2
HD
1 tháng 4 2017
7.12^8.5^4-6^9.20^4=7.96.20-54.80=9120
6^10.10^5-7,3^9.80^4=60.50-65.7.320=3000
ket qua rut gon thanh dap so 456 phan 150
8 tháng 10 2018
a)93/7:-3/7+178/7:3/7
3/7.(-93/7+178/7)=3/7.85/7=255/49
b)7.128.54-69.204/610.105-7.39.804
7.38.216.5429.39.54.28:210.310.25.55-7.39.216.54
=72.336.244.517
GN
GV Nguyễn Trần Thành Đạt
Giáo viên
24 tháng 6 2023
\(\dfrac{8^{14}}{4^4.64^5}=\dfrac{\left(2^3\right)^{14}}{\left(2^2\right)^4.\left(2^5\right)^5}=\dfrac{2^{42}}{2^8.2^{25}}=2^{42-\left(8+25\right)}=2^9\)
GN
GV Nguyễn Trần Thành Đạt
Giáo viên
24 tháng 6 2023
\(\dfrac{9^{10}.27^7}{81^7.3^{15}}=\dfrac{\left(3^2\right)^{10}.\left(3^3\right)^7}{\left(3^4\right)^7.3^{15}}=\dfrac{3^{20}.3^{21}}{3^{28}.3^{15}}=\dfrac{3^{20+21}}{3^{28+15}}=\dfrac{3^{41}}{3^{41}.3^2}=\dfrac{1}{3^2}=\dfrac{1}{9}\)
Y
15 tháng 8 2023
\(a,A=\dfrac{\dfrac{5}{4}+\dfrac{5}{5}+\dfrac{5}{7}-\dfrac{5}{11}}{\dfrac{10}{4}+\dfrac{10}{5}+\dfrac{10}{7}-\dfrac{10}{11}}\\ =\dfrac{5.\left(\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{1}{7}-\dfrac{1}{11}\right)}{10.\left(\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{1}{7}-\dfrac{1}{11}\right)}\\ =\dfrac{5}{10}\\ =\dfrac{1}{2}\)
Vậy \(A=\dfrac{1}{2}\)
\(b,B=\dfrac{2+\dfrac{6}{5}-\dfrac{6}{7}-\dfrac{6}{11}}{\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{7}-\dfrac{2}{11}}\\ =\dfrac{3.\left(\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{7}-\dfrac{2}{11}\right)}{\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{7}-\dfrac{2}{11}}\\ =3\)
Vậy \(B=3\)
5 tháng 7 2017
\(\left(\dfrac{2}{3}\right)^3.\left(\dfrac{-3}{4}\right)^2.\left(-1\right)^{2013}=\dfrac{8}{27}.\dfrac{9}{16}.\left(-1\right)=-\dfrac{1}{6}\)
\(\left(\dfrac{1}{5}\right)^{15}.\left(\dfrac{1}{4}\right)^{20}=\dfrac{1}{5^{12}}.\dfrac{1}{4^{20}}=5^{-12}.4^{-20}=125^{-4}.1024^{-4}=\left(125.1024\right)^{-4}=128000^{-4}\)
5 tháng 7 2017
\(\dfrac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}=\dfrac{2^{12}.3^{10}+2^3.3.5.2^9.3^9}{2^{12}.3^{12}+2^{11}.3^{11}}=\dfrac{2^{12}.3^{10}+2^{12}.2^{10}.5}{2^{12}.3^{12}+2^{11}.3^{11}}=\dfrac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^{11}\left(2.3+1\right)}=\dfrac{2.6}{3.7}=\dfrac{4}{7}\)
Ta có: \(\dfrac{7.12^8.5^4-6^9.20^4}{6^{10}.10^5-7.3^9.80^4}\)
\(=\dfrac{7.3^8.2^{16}.5^4-2^9.3^9.5^4.2^8}{2^{10}.3^{10}.2^5.5^5-7.3^9.2^{15}.2.5^4}\)
\(=\dfrac{2^{16}.5^4.3^8\left(7-2.3\right)}{2^{15}.3^9.5^4\left(15-7.2\right)}\)
\(=\dfrac{2^{15}.5^4.3^8.2}{2^{15}.3^8.3.5^4}\)
\(=\dfrac{2}{3}\).