\(\dfrac{2}{3}+\dfrac{-2}{3}=\) \(\dfrac{3}{5}+\dfrac{3}{-5}=\)
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i) \(\dfrac{2}{5}-\dfrac{1}{10}=\)
\(\dfrac{2}{5}+\left(-\dfrac{1}{10}\right)\) =
\(\dfrac{5}{6}-\dfrac{2}{3}=\)m
\(\dfrac{5}{6}+\left(-\dfrac{2}{3}\right)\)
2/3+(-2/3)=3/5+(3/-5)=0
i: 2/5-1/10=4/10-1/10=3/10
2/5+(-1/10)=4/10-1/10=3/10
5/6-2/3=5/6-4/6=1/6
5/6+(-2/3)=1/6