- tìm n \(\left(\frac{27}{46}\right)^9.n=\left(\frac{3}{46}\right)^{21}\)
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Trả lời :
a, x = (3,8)3 - (- 3,8)2
=> x = (3,8)3 - (3,8)2
=> x = (3,8)3 - 2
=> x = 3,8
Bài làm:
a) \(x=\left(3,8\right)^3\div\left(-3,8\right)^2\)
\(\Leftrightarrow x=\left(3,8\right)^3\div\left(3,8\right)^2\)
\(\Rightarrow x=3,8\)
b) đề sai sai ý bn
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Leftrightarrow\dfrac{46}{7}+\dfrac{81}{35}< =x< =\dfrac{49}{36}\)
\(\Leftrightarrow\dfrac{311}{35}< =x< =\dfrac{49}{36}\)
\(\Leftrightarrow x\in\varnothing\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)\(\frac{-5}{13}+\left(\frac{3}{5}+\frac{3}{13}-\frac{4}{10}\right)=\frac{-5}{13}-\frac{3}{5}-\frac{3}{13}+\frac{4}{10}=\left(\frac{-5}{13}-\frac{3}{13}\right)+\frac{4}{10}-\frac{3}{5}=\frac{-5-3}{13}+\left(\frac{4}{10}-\frac{6}{10}\right)=\frac{-8}{13}+\frac{-2}{10}=\frac{-80}{130}+\frac{-26}{130}=\frac{-106}{130}=\frac{-53}{65}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{\frac{25}{108}.\frac{1151}{5}+\frac{187}{4}}{\frac{139}{30}:\frac{-41}{21}}\)=\(\frac{\frac{5755}{108}+\frac{187}{4}}{\frac{-973}{410}}\)=\(\frac{\frac{8531}{84}}{\frac{-973}{410}}\)=-241,0180
\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right)\cdot230\frac{1}{5}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
\(=\frac{\left(\frac{53}{4}-\frac{59}{27}-\frac{65}{6}\right)\cdot\frac{1151}{5}+\frac{187}{4}}{\frac{139}{30}:\left(-\frac{41}{21}\right)}\)
\(=\frac{\frac{25}{108}\cdot\frac{1151}{5}+\frac{187}{4}}{\frac{139}{30}\cdot\left(-\frac{21}{41}\right)}=\frac{\frac{2701}{27}}{-\frac{973}{410}}\)
Tính nốt vì số dữ quá , lần sau để số ít thôi
\(\Leftrightarrow n=\dfrac{3^{21}}{46^{21}}:\dfrac{3^{27}}{46^9}=\dfrac{1}{46^{12}}\cdot\dfrac{1}{3^6}=\dfrac{1}{46^{12}\cdot3^6}\)