a + 5 / a - 5 = b + c / b - 6 ( a khác 5, b khác 6 ) Tìm a phần b
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Ta có:
\(\frac{a+5}{a-5}\)= \(\frac{b+6}{b-6}\)= \(\frac{a+5}{b-6}\)= \(\frac{a+5+a-5}{b-6+b-6}\) = \(\frac{2a}{2b}\) = \(\frac{a}{b}\)
Vậy \(\frac{a}{b}\) = \(\frac{a+5}{a-5}\)=\(\frac{b+6}{b-6}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Từ a+5/a-5=b+6/b-6
=>a+5/b+6=a-5/b-6
Áp dụng.... ta có:
a+5/b+6=a-5/b-6=(a+5+a-5)/(b+6+b-6)
=2a/2b=a/b. (1)
Vì a+5/b+6=a/b
Áp dụng.. ta có
a+5/b+6=a/b=a+5-a/b+6-b=5/6 (2)
Từ (1),(2)=>a/b=5/6(đpcm)
Tick nhé ,bài đúng 100%
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![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)
\(\frac{a-5}{a-5}+\frac{10}{a-5}=\frac{b-6}{b-6}+\frac{12}{b-6}\)
\(1+\frac{10}{a-5}=1+\frac{12}{b-6}\)
\(\frac{10}{a-5}=\frac{12}{b-6}\)
\(\Rightarrow12\left(a-5\right)=10\left(b-6\right)\)
\(\Rightarrow6\left(a-5\right)=5\left(b-6\right)\)
\(\Rightarrow6a-30=5b-30\)
\(\Rightarrow6a=5b\)
\(\Rightarrow\frac{a}{b}=\frac{5}{6}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\Rightarrow\frac{a+5}{b+6}=\frac{a-5}{b-6}\Rightarrow\frac{a}{b}=\frac{5}{6}\)
Cho \(\frac{a+5}{a-5}=\frac{b+6}{b-6}\) (a khác 5, b khác 6). Chứng minh \(\frac{a}{b}=\frac{5}{6}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : \(\frac{a+5}{b-5}\frac{b+6}{b-6}\)
=> \(\frac{a+5}{b+6}=\frac{a-5}{b-6}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có :
\(\frac{a+5}{b+6}=\frac{a-5}{b-6}=\frac{a+5+a-5}{b+6+b-6}=\frac{a+5-a+5}{b+5-b+5}\)
\(\frac{2a}{2b}=\frac{5.2}{6.2}=\frac{10}{12}\)
=> \(\frac{a}{b}=\frac{5}{6}\left(\text{đ}pcm\right)\)
Từ
\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\Rightarrow\frac{b-6}{a-5}=\frac{b+6}{a-5}\)
Áp dụng tính chất của dãy tỉ số bằng nhau . Ta có
\(\frac{b-6}{a-5}=\frac{b+6}{a+5}=\frac{b-6+b+6}{a-5+a+5}=\frac{2b}{2b}=\frac{b}{a}=\frac{b+6-b}{a+5-a}=\frac{6}{5}\)
\(\Rightarrow\frac{a}{b}=\frac{5}{6}\) (đpcm)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\Rightarrow\left(a+5\right)\left(b-6\right)=\left(a-5\right)\left(b+6\right)\)
\(\Rightarrow ab-6a+5b-30=ab+6a-5b-30\)
\(\Rightarrow5b=6a\Leftrightarrow\frac{a}{b}=\frac{5}{6}\)
(Đpcm)
Từ \(\frac{a+5}{a-5}=\frac{b+6}{b-6}\Rightarrow\frac{b-6}{a-5}=\frac{b+6}{a+5}\)
Áp dụng t/c dãy tỉ số bằng nhau :
\(\frac{b-6}{a-5}=\frac{b+6}{a+5}=\frac{\left(b+6\right)-\left(b-6\right)}{\left(a+5\right)-\left(a-5\right)}=\frac{12}{10}=\frac{6}{5}\)
\(\Rightarrow5\left(b-6\right)=6\left(a-5\right)\Leftrightarrow5b=6a\Leftrightarrow\frac{a}{b}=\frac{5}{6}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Vì \(\frac{a+5}{a-5}=\frac{b+6}{b-6}\Rightarrow\frac{a+5}{b+6}=\frac{a-5}{b-6}\)
Áp dụng TC DTSBN ta có :
\(\frac{a+5}{b+6}=\frac{a-5}{b-6}=\frac{\left(a+5\right)+\left(a-5\right)}{\left(b+c\right)+\left(b-6\right)}=\frac{2a}{2b}=\frac{a}{b}\) (1)
\(\frac{a+5}{b+6}=\frac{a-5}{b-6}=\frac{\left(a+5\right)-\left(a-5\right)}{\left(b+6\right)-\left(b-6\right)}=\frac{10}{12}=\frac{5}{6}\)(2)
Từ (1) ; (2) \(\Rightarrow\frac{a}{b}=\frac{5}{6}\)(đpcm)