(187+23)-(20+187)
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![](https://rs.olm.vn/images/avt/0.png?1311)
Cách 1 : tính bình thường
(187-23)-(20-180)
=164-(-160)
=164+160
=324
Cách 2: phá ngoặc rồi tính
(187-23)-(20-180)
=187-23-20+180
=164-20+180
=144+180
=324
![](https://rs.olm.vn/images/avt/0.png?1311)
7: =-1+8=7
6: \(=-\left(8\cdot125\right)\cdot\left(2\cdot5\right)\cdot\left(25\cdot4\right)=-1000000\)
5: =-50+19+143+79-25-48
=-75+98+95
=23+95
=118
4: =37x9+17x9-35x9-35x11
=18+153-385
=-214
![](https://rs.olm.vn/images/avt/0.png?1311)
3: =187-23-20+180
=367-43
=324
4: \(=37\cdot9+17\cdot9-35\cdot9-35\cdot11=19\cdot9-385\)
\(=171-385=-214\)
5: =-50+19+143+79-25-48
=-75+94+95
=20+94
=114
![](https://rs.olm.vn/images/avt/0.png?1311)
Trả lời:
b.(-50+19+143)-(-79+25+48)
= 112 - (-6)
=118
a.(187-23)-(20-180)
= 164- (-160)
=324
~Học tốt~
![](https://rs.olm.vn/images/avt/0.png?1311)
1) 125.(-24) + 24.225.
\(=24\left(-125+225\right)=24.100=2400.\)
2) 512.(2 – 128) – 128. (-512).
\(=512\left(2-128+128\right)=512.2=1024.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) ( -125) + 100 + 80 + 125 + 20
= [ ( -125)+125] + ( 80+20) + 100
= 0 + 100 + 100 = 200
b) 27 + 55 + (-17) + ( - 55)
= [ 27+(-17)] +[ 55+(-55)]
= 10 + 0 = 10
c) (-92) + (-251) + (-8) + 251
= [ (-92) + (-8)] + [ (-251)+251]
= (-100) + 0 = -100.
d) (-31) + (-95) +131 + (-5)
= [ (-31)+131] +[ (-95)+(-5)] = 100 + (-100) = 0
e) (187 - 23) - (20-180)
= 187 - 23 - 20 + 180 = (187-180) - (23-20) = 7 - 3 = 4
g) (-50+19+143) - (-79+25+48)
= -50+19+143 + 79 - 25 - 48
= [ -50-25] + (19 + 79) + 143 - 48
= -75 + 98 + 143 - 48 = 143 - 75 + ( 98 -48)
= 68 + 50 = 118
![](https://rs.olm.vn/images/avt/0.png?1311)
\(B=\left(17+\dfrac{1}{25}-16-\dfrac{11}{15}\right)\cdot\dfrac{75}{23}+\dfrac{75}{23}\cdot\dfrac{23}{75}\)
\(=\dfrac{23}{75}\cdot\dfrac{75}{23}+1=1+1=2\)
187+23-20-187=3
Hoặc
(187+23)-(20+187)=210-207=3