Giúp mình nha team thức khuya ơi!
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Những câu hỏi liên quan
MN
29 tháng 6 2021
1. To stay healthy you eat more vegetable and you eat less high - fat food.
2. To prevent flu, we eat a lot of garlic and we keep our bodies especially feet warm.
3. It began to rain so I opened my umbrella.
4. It began to rain but he didn’t open his umbrella.
5. He worked hard so he could earn much money.
6. Study hard or you will fail the exam.
7. Dan didn’t study for the exam but Lan did.
8. I understand your point of view but I don’t agree with it.
9. He lied to her. However, she still likes and trusts him.
K
29 tháng 6 2021
1. To stay healthy you eat more vegetable and less high - fat food.
2. To prevent flu, we eat a lot of garlic and keep our bodies especially feet warm.
3. It began to rain, so I opened my umbrella.
4. It began to rain but he didn’t open his umbrella.
5. He worked hard, so he could earn much money.
6. Study hard or you will fail the exam.
7. Dan didn’t study for the exam, but Lan did.
8. I understand your point of view; however, I don’t agree with it.
9. He lied to her; however, he still likes and trusts him.
30 tháng 11 2021
uầy bn cx bt biệt đội sinh tố à :) ? mik là fan zeros :)
NM
1
4 tháng 2 2021
ĐKXĐ: \(x\notin\left\{-7;3;-3\right\}\)
a) Ta có: \(B=\left(\dfrac{x^2+1}{x^2-9}-\dfrac{x}{x+3}+\dfrac{5}{x-3}\right):\left(\dfrac{2x+10}{x+3}-1\right)\)
\(=\left(\dfrac{x^2+1}{\left(x-3\right)\left(x+3\right)}-\dfrac{x\left(x-3\right)}{\left(x+3\right)\left(x-3\right)}+\dfrac{5\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}\right):\left(\dfrac{2x+10}{x+3}-\dfrac{x+3}{x+3}\right)\)
\(=\dfrac{x^2+1-x^2+3x+5x+15}{\left(x-3\right)\left(x+3\right)}:\dfrac{2x+10-x-3}{x+3}\)
\(=\dfrac{8x+16}{\left(x-3\right)\left(x+3\right)}\cdot\dfrac{x+3}{x+7}\)
\(=\dfrac{8x+16}{\left(x-3\right)\left(x+7\right)}\)
b) Ta có: |x-1|=2
\(\Leftrightarrow\left[{}\begin{matrix}x-1=2\\x-1=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\left(loại\right)\\x=-1\left(nhận\right)\end{matrix}\right.\)
Thay x=-1 vào biểu thức \(B=\dfrac{8x+16}{\left(x-3\right)\left(x+7\right)}\), ta được:
\(B=\dfrac{8\cdot\left(-1\right)+16}{\left(-1-3\right)\left(-1+7\right)}=\dfrac{-8+16}{-4\cdot6}=\dfrac{8}{-24}=\dfrac{-1}{3}\)
Vậy: Khi x=-1 thì \(B=\dfrac{-1}{3}\)
c) Để \(B=\dfrac{x+5}{6}\) thì \(=\dfrac{8x+16}{\left(x-3\right)\left(x+7\right)}=\dfrac{x+5}{6}\)
\(\Leftrightarrow6\left(8x+16\right)=\left(x+5\right)\left(x-3\right)\left(x+7\right)\)
\(\Leftrightarrow48x+96=\left(x^2-3x+5x-15\right)\left(x+7\right)\)
\(\Leftrightarrow\left(x^2+2x-15\right)\left(x+7\right)=48x+96\)
\(\Leftrightarrow x^3+7x^2+2x^2+14x-15x-105-48x-96=0\)
\(\Leftrightarrow x^3+9x^2-49x-201=0\)
\(\Leftrightarrow x^3+3x^2+6x^2+18x-67x-201=0\)
\(\Leftrightarrow x^2\left(x+3\right)+6x\left(x+3\right)-67\left(x+3\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left(x^2+6x-67\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left(x^2+6x+9-76\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left[\left(x+3\right)^2-76\right]=0\)
\(\Leftrightarrow\left(x+3\right)\left(x+3-2\sqrt{19}\right)\left(x+3+2\sqrt{19}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+3=0\\x+3-2\sqrt{19}=0\\x+3+2\sqrt{19}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-3\left(loại\right)\\x=2\sqrt{19}-3\left(nhận\right)\\x=-2\sqrt{19}-3\left(nhận\right)\end{matrix}\right.\)
Vậy: Để \(B=\dfrac{x+5}{6}\) thì \(x\in\left\{2\sqrt{19}-3;-2\sqrt{19}-3\right\}\)
giúp mình với mấy bạn ơi, mình cảm ơn trước nha!!!!!!!
14 tháng 4 2022
a: \(=\left(\dfrac{10}{3}+\dfrac{5}{2}\right):\left(\dfrac{19}{6}-\dfrac{21}{5}\right)-\dfrac{11}{31}\)
\(=\dfrac{35}{6}:\dfrac{95-126}{30}-\dfrac{11}{31}\)
\(=\dfrac{35}{6}\cdot\dfrac{30}{-31}-\dfrac{11}{31}\)
\(=\dfrac{-35\cdot5}{31}-\dfrac{11}{31}=\dfrac{-186}{31}=-6\)
b: \(=\left(-8\right)\cdot\dfrac{1}{2}:\left(\dfrac{9}{4}-\dfrac{7}{6}\right)=-4:\dfrac{27-14}{12}=\dfrac{-4\cdot12}{13}=\dfrac{-48}{13}\)
KN
2
4 tháng 12 2021
\(p=738mmHg=98391,9312Pa\)
Áp suất tại chân cột:\(p_2\)
Áp suất tương ứng với độ cao cột thủy ngân:
\(p=d\cdot h\Rightarrow p=\left(p_2-738\right)\cdot136000Pa\)
TK
4 tháng 12 2021
Đổi 738 mmHg =0,738 mHg
\(P=d_{Hg}.h=136000\cdot0,738=100368\left(Pa\right)\)
27 tháng 10 2021
Bài 4:
a) áp dụng pi-ta-go ta có:\(AB^2+AC^2=BC^2\Rightarrow BC=\sqrt{15^2+20^2}=25\)
áp dụng HTL ta có: \(AB.AC=BC.AH\Rightarrow\dfrac{15.20}{25}=AH\Rightarrow AH=12\)
b) áp dụng HTL và ΔAHB ta có: \(AI.AB=AH^2\)
áp dụng HTL và ΔAHC ta có: \(AJ.AC=AH^2\)
\(\Rightarrow AI.AB=AJ.AC\)
1 what a bright room
2 i have played soccer for 5 years
3 my school is different from yours
4 nick's hobby is carving eggshells