rút gọn rồi quy đồng mẫu các phân số sau 3.4+3.7 / 6.5+9 và 6.9-2.17 / 63.3-11
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a: 27/-180=-27/180=-3/20=-21/140
-6/-35=6/35=24/120
-3/-28=3/28=15/140
b: \(\dfrac{3\cdot4+3\cdot7}{6\cdot5+9}=\dfrac{3\left(4+7\right)}{30+9}=\dfrac{11}{13}=\dfrac{2849}{13\cdot259}\)
\(\dfrac{6\cdot9-2\cdot17}{63\cdot6-119}=\dfrac{54-34}{259}=\dfrac{20}{259}=\dfrac{260}{259\cdot13}\)
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\(\dfrac{3\cdot4+3\cdot7}{6\cdot5+9}=\dfrac{3\cdot11}{30+9}=\dfrac{33}{39}=\dfrac{11}{13}=\dfrac{77}{91}\)
\(\dfrac{6\cdot9-2\cdot17}{63\cdot3-119}=\dfrac{54-34}{189-119}=\dfrac{20}{70}=\dfrac{2}{7}=\dfrac{26}{91}\)
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a) -15/90= -5/30= -1/6
120/600=1/5
-75/150= -25/50= -1/2
b)3.4+3.7/6.5+9
=3.(4+7)/3.2+3 .3
=11/2+3.3
=11/11=1
6.9-2.17/63.3-11.9
=2.3.3.3-2.17/7.3.3-11.3.3
=2-2.17/7.3-11
= 2-2.17/10
=2-2.17/2.5
=2-17/5
=-15/5=-3
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Ta có:
\(\frac{3\cdot4+3\cdot7}{6\cdot5+9}=\frac{3\cdot4+3\cdot7}{3\cdot2\cdot5+3\cdot3}=\frac{3\cdot4+3\cdot7}{3\cdot10+3\cdot3}=\frac{3\cdot\left(4+7\right)}{3\cdot\left(10+3\right)}=\frac{4+7}{10+3}=\frac{11}{13}\)
\(\frac{6\cdot9-2\cdot17}{63\cdot3-119}=\frac{3\cdot2\cdot3\cdot3-2\cdot17}{3\cdot7\cdot3\cdot3-7\cdot17}=\frac{2\cdot27-2\cdot17}{7\cdot27-7\cdot17}=\frac{2\cdot\left(27-17\right)}{7\cdot\left(27-17\right)}=\frac{2\cdot10}{7\cdot10}=\frac{2}{7}\)
MSC của \(\frac{11}{13}\) và \(\frac{2}{7}\) là 91 nên ta có:
\(\frac{11}{13}=\frac{11\cdot7}{13\cdot7}=\frac{77}{91}\)
\(\frac{2}{7}=\frac{2\cdot13}{7\cdot13}=\frac{26}{91}\)
Vậy quy đồng \(\frac{11}{13}\) và \(\frac{2}{7}\) được \(\frac{77}{91}\) và \(\frac{26}{91}\)
\(\frac{3.4+3.7}{6.5+9}=\frac{3\left(4+7\right)}{30+9}=\frac{3.11}{39}=\frac{33}{39}=\frac{11}{13}\)
\(\frac{6.9-2.17}{63.3-11}=\frac{54-54}{63.3-11}=0\)