Tính (1-1/2)x(1-1/3)x(1-1/4)x( 1-1/5)x .........( 1-1/2015)x(1-1/2016)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Cách 1:
Xét số bị trừ, ta có:
(2/3 + 3/4 + 4/5 + ... + 2016/2017) x (1/2 + 2/3 + 3/4 + ... + 2015/2016)
= (2/3 + 3/4 + 4/5 + ... + 2015/2016 + 2016/2017) x (1/2 + 2/3 + 3/4 + ... + 2015/2016)
= (2/3 + 3/4 + 4/5 + ... + 2015/2016) x (1/2 + 2/3 + 3/4 + ... + 2015/2016) + 2016/2017 x (1/2 + 2/3 + 3/4 + ... + 2015/2016)
Xét số trừ, ta có:
(1/2 + 2/3 + 3/4 + ... + 2016/2017) x (2/3 + 3/4 + 4/5 + ... + 2015/2016)
= (1/2 + 2/3 + 3/4 + ... + 2015/2016 + 2016/2017) x (2/3 + 3/4 + 4/5 + ... + 2015/2016)
= (1/2 + 2/3 + 3/4 + ... + 2015/2016) x (2/3 + 3/4 + 4/5 + ... + 2015/2016) + 2016/2017 x (2/3 +3/4 + 4/5 + ... + 2015/2016) =
Ta thấy số bị trừ và số trừ có số hạng giống nhau là:
(2/3 +3/4 + 4/5 + ... + 2015/2016) x (1/2 + 2/3 + 3/4 + ... + 2015/2016)
Nên phép trừ trên có thể viết lại:
2016/2017 x (1/2 + 2/3 + 3/4 + ... + 2015/2016) - 2016/2017 x (2/3 + 3/4 + 4/5 + ... + 2015/2016)
= 2016/2017 x [(1/2 + 2/3 + 3/4 + ... + 2015/2016) - (2/3 +3/4 + 4/5 + ... + 2015/2016)]
= 2016/2017 x 1/2
= 1008/2017
Cách 2:
![](https://rs.olm.vn/images/avt/0.png?1311)
2A=2/1.2.3 + 2/2.3.4 + 2/3.4.5 + ...+2/2014.2015.2016
Ta có: 2/1.2.3=1/1.2-1/2.3; 2/2.3.4=1/2.3-1/3.4; 2/3.4.5=1/3.4-1/4.5; ....; 2/2014.2015.2016=1/2014.2015-1/2015.2016
=> 2A=1/1.2-1/2015.2016
=> 2A < 1/2 => A < 1/4
![](https://rs.olm.vn/images/avt/0.png?1311)
1) 9 x 10 + 10 x 11 + 11 x 12 + ....+ 2015 x 2016
=9x10x11-8x9x10+10x11x12-9x10x11+...+2015x2016x2017-2014x2015x2013
=2015x2016x2017-8x9x10
=8193537360
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(1+2+3+4+5+......+2015+2016\right)\cdot\left(9\cdot11-100+1\right)\)
\(=\left(1+2+3+4+5+......+2015+2016\right)\cdot\left(99-100+1\right)\)
\(=\left(1+2+3+4+5+......+2015+2016\right)\cdot\left(-1+1\right)\)
\(=\left(1+2+3+4+5+......+2015+2016\right)\cdot0\)
\(=0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Tta thấy 9x11-100+1=99-100+1
=-1+1=0
Mà số nào nhân với 0 cũng bằng 0 nên đáp án bàng 0 nha bạn
Nhớ ủng hộ mk nha
( 1+2+3+4+5+....+2015+2016) x ( 99-100+1)=( (2016-1):1+1) x 0 = 2016 x 0 = 0
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{5932+6001x5931}{5932x6001-69}=\frac{6001x5931+5932}{5931x6001+6001-69}=\frac{6001x5931+5932}{6001x5931+5932}=1\)
\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)..........\left(1-\frac{1}{2016}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.........\frac{2015}{2016}\)
\(=\frac{1.2.......2015}{2.3.......2016}\)
\(=\frac{1}{2016}\)
\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)........\left(1-\frac{1}{2016}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.......\frac{2015}{2016}=\frac{1}{2016}\)