Bài 1:1. Rút gọn:a) \(A=\frac{9^3.25^3}{18^2.125^2}\)b) \(B=\frac{18}{37}+\frac{8}{2017}+\frac{19}{37}-1\frac{2009}{2017}+\frac{2017}{2018}\)2.CHO \(M=\frac{2}{5.14}+\frac{2}{7.18}+\frac{2}{9.22}+\frac{2}{11.26}+\frac{2}{13.30}\).so sánh M &\(\frac{3}{46}\)Bài 2:...
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Bài 1:1. Rút gọn:
a) \(A=\frac{9^3.25^3}{18^2.125^2}\)
b) \(B=\frac{18}{37}+\frac{8}{2017}+\frac{19}{37}-1\frac{2009}{2017}+\frac{2017}{2018}\)
2.CHO \(M=\frac{2}{5.14}+\frac{2}{7.18}+\frac{2}{9.22}+\frac{2}{11.26}+\frac{2}{13.30}\).so sánh M &\(\frac{3}{46}\)
Bài 2: Tim \(x\),biết:
a) \(\left(2x-1\right)^2-25\)
b)\(\frac{148-x}{25}+\frac{164-x}{23}+\frac{186-x}{21}+\frac{199-x}{19}=10\)
bài 1.a)\(A=\frac{9^3.25^3}{18^2.125^2}=\frac{3^6.5^6}{2^2.3^4.5^6}=\frac{9}{4}\)
b) \(B=\frac{18}{37}+\frac{19}{37}+\frac{8}{2017}-\frac{4026}{2017}+\frac{2017}{2018}\)
\(=1-\frac{4014}{2017}+\frac{2017}{2018}=\frac{1997}{2017}+\frac{2017}{2018}\)