X-2,5=1/3+2/3xX
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e) (x + 1) + (x + 2) + .... + (x + 211) = 23632
(x + x + .... + x) + (1 + 2 + ... + 211) = 23632
211x + 22366 = 23632
211x = 23632 - 22366
211x = 1266
=> x= 6
f) (1 + 3 + 5 + 7 + .... + 2009) + x = 1010026
Số số hạng của 1 + 3 + 5 + 7 + .... + 2009 là: (2009 - 1) : 2 + 1 = 1005
Tổng của 1 + 3 + 5 +... + 2009 là: (1 + 2009) x 1005 : 2 = 1010025
Ta được : 1010025 + x = 1010026
=> x = 1010026 - 1010025 = 1
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a. \(\dfrac{5}{7}+\dfrac{4}{3}:x=\dfrac{1}{7}\)
<=> \(\dfrac{5}{7}+\dfrac{4}{3}.\dfrac{1}{x}=\dfrac{1}{7}\)
<=> \(\dfrac{5}{7}+\dfrac{4}{3x}=\dfrac{1}{7}\) ĐKXĐ: x \(\ne\) 0
<=> \(\dfrac{15x}{21x}+\dfrac{28}{21x}=\dfrac{3x}{21x}\)
<=> 15x + 28 = 3x
<=> 15x - 3x = -28
<=> 12x = -28
<=> x = \(\dfrac{-28}{12}=-\dfrac{7}{3}\)
b. \(\dfrac{5}{3}x.\dfrac{-1}{4}=\dfrac{2}{6}\)
<=> \(\dfrac{-5x}{12}=\dfrac{2}{6}\)
<=> -5x . 6 = 12 . 2
<=> -30x = 24
<=> x = \(-\dfrac{4}{5}\)
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a) \(\frac{2}{3}:\frac{2}{3}\times x=1\)
\(1\times x=1\)
x = 1
b) \(x+x:5\times7,5+x:2\times9=315\)
\(x+x\cdot\frac{1}{5}\cdot7,5+x\cdot\frac{1}{2}\cdot9=315\)
\(x\cdot\left(1+\frac{1}{5}.7,5+\frac{1}{2}.9\right)=315\)
x.7 = 315
x = 45
Dấu . là dấu nhân nha
Tìm x :
a) 2/3 : 2/3 × X = 1
1 × X = 1
X = 1 : 1
X = 1
b) X + X : 5 × 7,5 + X : 2 × 9 = 315
X + X × 1/5 × 7,5 + X × 1/2 × 9 = 315
X × 1 + X × 1,5 + X × 4,5 = 315
X × ( 1 + 1,5 + 4,5 ) = 315
X × 7 = 315
X = 315 : 7
X = 45
VẬY X = 45
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\(x-2.5=\frac{1}{3}+\frac{2x}{3}\)
\(\Leftrightarrow\frac{3\left(x-2,5\right)}{3}=\frac{2x+1}{3}\)
\(\Leftrightarrow3x-7,5=2x+1\)
\(\Leftrightarrow x=8,5\)
\(x-2,5=\frac{1}{3}+\frac{2}{3}x\)
\(x-\frac{2}{3}x=\frac{1}{3}+2,5\)
\(\frac{1}{3}x=\frac{1}{3}+\frac{5}{2}\)
\(\frac{1}{3}x=\frac{17}{6}\)
\(x=\frac{17}{2}\)