tính A=-2014-(-2014)+(2013)^0.(-1)^3+(-2)^3+12/25-17/37+13/25-20/37
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A= - 2014 +2014 +1 . (-1) +(- 8) - 12/25 - 17/37 +13/25 - 20/37
A = ( -2014+2014) + ( - 1) +(-8) - (12/25 - 13/25 ) - (17/37 +20/37)
A = 0 +(-1) + (-8) +1/25 -1
A =(-9) +0,04 - 1
A = - 9,96
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2575+37-2576-29\)
\(=2612-2576-29\)
\(=36-29=7\)'
\(35+35+36+37-14-15-16-17\)
\(=70+\left(36-16\right)+\left(37-17\right)-14-15\)
\(=70+20+20-14-15\)
\(=90+6-15\)
\(=96-15=81\)
\(13\cdot\left(-12\right)+87.\left(-12\right)\)
\(=\left(-12\right)\cdot\left(13+87\right)\)
\(=\left(-12\right)\cdot100=-1200\)
\(26\cdot17+17\cdot74\)
\(=\left(26+74\right)\cdot17\)
\(=100\cdot17=1700\)
\(25\cdot\left(-18\right)+25\left(-82\right)\)
\(=25\cdot\left[\left(-18\right)+\left(-82\right)\right]\)
\(=25\cdot\left(-100\right)=\left(-2500\right)\)
\(25+37-48-25-37\)
\(=\left(25-25\right)+\left(37-37\right)-48\)
\(=0+0-48\)
\(=0-48=\left(-48\right)\)
\(\left(-16\right)+24+16-34\)
\(=\left[\left(-16\right)+16\right]+\left(24-34\right)\)
\(=0+\left(-10\right)=\left(-10\right)\)
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a)(-12)+(-13)+36+(-1)
={[(-12)+(-1)]+(-13)}+36
={(-13)+(-13)}+36
=(-26)+36
=10
b)25+37-48-25-37
=[25+(-25)]+(37-37)-48
=0+0-48
=0-48
=-48
c)2575+37-2576-29
=(2575-2576)+(37-29)
=(-1)+8
=7
d)34+35+36+37-14-15-16-17
=(34-14)+(35-15)+(36-16)+(37-17)
=10+10+10+10
=10.4
=40
*Lưu ý:Dấu . là dấu x
a/ (-12)+(-13)+36+(-1)
=(-12)+(-13)+(-1)+36
=(-26)+36
=10
b/ 25+37-48-25-37
=(25-25)+(37-37)-48
=0+0-48
=-48
c/ 2575+37-2576-29
=2575-2576+37-29
=(-1)+8
=-7
tick cho mình tròn 510 nha
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15) $|-18| + (-12)=18-12=6$
16) $17+ |-33|=17+33=50$
17) $(– 20) + |-88|=-20+88=68$
18) $|-3| + |5|=3+5=8$
19) $|-37| + |15|=37+15=52$
20) $|-37| + (-|15|)=37-15=22$
21) $(-|-32|) + |5| 22)(-|-22|)+ (-|16|)=-32+5.22-22=-32+4.22=-32+88=56$
23) $(-23) + 13 + ( - 17) + 57=-23+13-17=-40+13=-23$
24) $14 + 6 + (-9) + (-14)=14+6-9-14=6-9=-3$
25) $(-123) +|-13|+ (-7)=-123+13-7=-110-7=-117$
26) $|0|+|45|+(-|-455)|+|-796|=0+45-455+796=-410+796=386$
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
a) \(\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\)
\(=\)\(\frac{1}{2}\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}+\frac{2}{13.15}\right)\)
\(=\)\(\frac{1}{2}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}\right)\)
\(=\)\(\frac{1}{2}\left(\frac{1}{3}-\frac{1}{15}\right)\)
\(=\)\(\frac{1}{2}.\frac{4}{15}\)
\(=\)\(\frac{2}{15}\)
Ta có :
\(c)\)\(\frac{1}{1000}+\frac{13}{1000}+\frac{25}{1000}+\frac{37}{1000}+...+\frac{229}{1000}\)
\(=\)\(\frac{1+13+25+37+...+229}{1000}\)
Xét tổng \(1+13+25+37+...+229\):
Số số hạng : \(\left(229-1\right):12+1=20\) ( số hạng )
Tổng : \(\frac{\left(229+1\right).20}{2}=2300\)
Do đó :
\(\frac{1+13+25+37+...+229}{1000}=\frac{2300}{1000}=\frac{23}{10}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1, Thực hiện phép tính :
a) \(\left(-37\right)+4\cdot\left|-6\right|\)
\(=-\left(37\right)+4\cdot6\)
\(=-37+24\)
\(=13\)
b) \(17\cdot85+15\cdot17-120\)
\(=17\cdot\left(85+15\right)-120\)
\(=17\cdot100-120\)
\(=1700-120\)
\(=1580\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1. \(G=2016.2016=\left(2014+2\right)\left(2018-2\right)=2014.2018-4028+4036-4=2014.2018+4\)
vì 2014.2018+4 >2014.2018
=> G>H
\(\frac{2016.2016}{2013.2019}=\frac{\left(2013+3\right)\left(2019-3\right)}{2013.2019}=\frac{2013.2019-6039+6057-9}{2013.2019}=\frac{2013.2019+9}{2013.2019}=1+\frac{9}{2013.2019}\)
vì \(1+\frac{9}{2013.2019}>1\)
\(\frac{2016.2016}{2013.2019}>1\)