so sanh a voi b biet;
a=75/100+78/21+19/32+22/21+13/32
b=(27,5x0,1+2,5x0,1)x2
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TG
3
T
19 tháng 10 2018
\(A=2^{2019}-\left(2^{2018}+2^{2017}+2^{2016}+.....+2^1+2^0\right)\)
Đặt: \(B=2^{2018}+2^{2017}+2^{2016}+....+2^1+2^0\)
\(\Rightarrow2B=\left(2^{2018}+2^{2017}+2^{2016}+...+2^1+2^0\right)\)
\(\Rightarrow2B-B=\left(2^{2019}+2^{2018}+2^{2017}+...+2^2+2\right)-\left(2^{2018}+2^{2017}+2^{2016}+...+2^1+2^0\right)\)
\(\Rightarrow B=2^{2019}-1\)
\(\Rightarrow A=2^{2019}-\left(2^{2018}+2^{2017}+2^{2016}+.....+2^1+2^0\right)\)
\(=2^{2019}-\left(2^{2019}-1\right)=2^{2019}+2^{2019}+1>1\)
NT
0
NL
1
16 tháng 8 2015
\(S=1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{45}\)
\(\frac{S}{2}=\frac{1}{2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+...+\frac{1}{9\cdot10}\)
\(\frac{S}{2}=\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\)
\(\frac{S}{2}=1-\frac{1}{10}\)
\(\frac{S}{2}=\frac{9}{10}\)
\(S=\frac{9}{5}
NT
0
NT
0
ta có: \(A=\frac{75}{100}+\frac{78}{21}+\frac{19}{32}+\frac{22}{21}+\frac{13}{32}\)
\(A=\frac{3}{4}+\left(\frac{78}{21}+\frac{22}{21}\right)+\left(\frac{19}{32}+\frac{13}{32}\right)\)
\(A=\frac{3}{4}+4+\frac{16}{21}+1\)
\(A=5+\frac{3}{4}+\frac{16}{21}\)
\(B=\left(27,5\times0,1+2,5\times0,1\right)\times2\)
\(B=\left[\left(27,5+2,5\right)\times0,1\right]\times2\)
\(B=\left(30\times0,1\right)\times2\)
\(B=5\)
\(\Rightarrow5+\frac{3}{4}+\frac{16}{21}>5\)
\(\Rightarrow A>B\)