Đặt x=a-2,ta có : \(P=\frac{\sqrt{x}-2}{3}.\left(\frac{\sqrt{x}}{3+\sqrt{x}}+\frac{x+9}{9-x}\right):\left(\frac{3\sqrt{x}+1}{x-3\sqrt{x}}-\frac{1}{\sqrt{x}}\right)\)

\(=\frac{\sqrt{x}-2}{3}.\left(\frac{\sqrt{x}\left(3-\sqrt{x}\right)+x+9}{\left(3-\sqrt{x}\right)\left(3+\sqrt{x}\right)}\right):\left(\frac{3\sqrt{x}+1-\left(\sqrt{x}-3\right)}{\sqrt{x}\left(\sqrt{x}-3\right)}\right)\)

\(=\frac{\sqrt{x}-2}{3}.\left(\frac{3\left(\sqrt{x}+3\right)}{\left(3-\sqrt{x}\right)\left(3+\sqrt{x}\right)}\right):\left(\frac{2\left(\sqrt{x}+2\right)}{\sqrt{x}\left(\sqrt{x}-3\right)}\right)\)

\(=\frac{\sqrt{x}-2}{3}.\frac{3}{3-\sqrt{x}}.\frac{\sqrt{x}\left(\sqrt{x}-3\right)}{2\left(\sqrt{x}+2\right)}\)

\(=\frac{-\sqrt{x}\left(\sqrt{x}-2\right)}{2\left(\sqrt{x}+2\right)}\)

a) Ta có : \(A=\frac{3x+5}{x+4}=\frac{3x+12-7}{x+4}=\frac{3\left(x+4\right)-7}{x+4}=3-\frac{7}{x+4}\)

Vì \(3\inℤ\Rightarrow\frac{-7}{x+4}\inℤ\Rightarrow-7⋮x+4\Rightarrow x+4\inƯ\left(-7\right)\)

=> \(x+4\in\left\{1;-1;-7;7\right\}\Rightarrow x\in\left\{-3;-5;-11;7\right\}\)

b) Ta có B = \(\frac{10x^2-7x-5}{2x-3}=\frac{10x^2-15x+8x-12+7}{2x-3}=\frac{5x\left(2x-3\right)+4\left(2x-3\right)+7}{2x-3}\)

\(=\frac{\left(5x+4\right)\left(2x-3\right)+7}{2x-3}=5x+4+\frac{7}{2x-3}\)

Vì \(\hept{\begin{cases}5x\inℤ\\4\inℤ\end{cases}\Rightarrow\frac{7}{2x-3}\inℤ\Rightarrow7⋮2x-3\Rightarrow2x-3\inƯ\left(7\right)\Rightarrow2x-3\in\left\{1;7;-1;-7\right\}}\)

=> \(x\in\left\{2;5;1;-2\right\}\)

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Mình không hiểu câu hỏi của bạn ạ !! Cậu hỏi là : thời gian làm 1 bài buổi sáng hơn thời gian 1 bài buổi chiều hay là tổng thời gian làm buổi sáng hơn tổng thời gian buổi chiều ạ ??

a)\(280-\left(x-140\right):35=270\)

\(\Leftrightarrow\left(x-140\right):35=10\)

\(\Leftrightarrow x-140=350\)

\(\Leftrightarrow x=490\)

b) \(\left(190-2x\right):35-32=16\)

\(\Leftrightarrow\left(190-2x\right):35=48\)

\(\Leftrightarrow190-2x=1680\)

\(\Leftrightarrow2x=-1490\Leftrightarrow x=-745\)

c) \(720:\left[41-\left(2x-5\right)\right]=2^3.5\)

\(\Leftrightarrow720:\left[41-\left(2x-5\right)\right]=40\)

\(\Leftrightarrow41-\left(2x-5\right)=18\)

\(\Leftrightarrow2x-5=23\)

\(\Leftrightarrow2x=28\Leftrightarrow x=14\)

280-(x-140):35=270

(x-140):35=280-270

(x-140):35=10

(x-140)=10×35

(x-140)=350

x=350-140

x=210

vậy x=210

(192-2x):35-32=16

(192-2x):35=16+32

(192-2x):35=48

(192-2x)=48×35

(192-2x)=1680

2x=192-1680

2x=-1488

x=-1488:2

x=-744

vậy x=-744

Theo đề bài ta có : ( ab + 7ab ) : 2 = 428

                        => ab + 700 + ab = 428 . 2

                        => ab.2 + 700 = 856

                        => ab.2 = 156

                        => ab = 78

Thế vị trí tương ứng => Hai số cần tìm là 78 và 778 

Tổng 2 số là 428x2=856

=> ab+7ab=ab+700+ab=2xab+700=856 => 2xab=156 => ab=78

1.My address is ...... 

2. My village is very beautiful and peaceful

3. In the morning, I often water the flower 

    In the afternoon, I often clean the house

    In the evening, I often watch TV

4.I often go to the library two times a week

5.Yes, I did

6.At the party, I sang a lot of songs, ate birthday cake and danced

                                                            CHÚC BẠN HỌC TỐT

1 . My is address .......

2. My village is very beautiful and peaceful

3. In the morning , I often water the flo

Ta có : \(\left|x-\frac{1}{3}\right|=\frac{5}{6}\)

\(\Leftrightarrow\orbr{\begin{cases}x-\frac{1}{3}=\frac{5}{6}\\x-\frac{1}{3}=-\frac{5}{6}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{7}{6}\\x=\frac{-1}{2}\end{cases}}\)

Ta có :\(\left|x-\frac{1}{3}\right|=\frac{5}{6}\)

=> \(\orbr{\begin{cases}x-\frac{1}{3}=\frac{5}{6}\\x-\frac{1}{3}=-\frac{5}{6}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{5}{6}+\frac{1}{3}\\x=-\frac{5}{6}+\frac{1}{3}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{7}{6}\\x=-\frac{1}{2}\end{cases}}\)

Vậy \(x\in\left\{\frac{7}{6};-\frac{1}{2}\right\}\)