2021.(2020+2022)-2020.(2021+2022)
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\(\left(x+1\right)^2-3\left(x+1\right)=\left(x+1\right)\left(x+1-3\right)=\left(x+1\right)\left(x-2\right)\)
\(2x\left(x-2\right)-\left(x-2\right)^2=\left(x-2\right)\left[2x-\left(x-2\right)\right]=\left(x-2\right)\left(2x-x+2\right)=\left(x-2\right)\left(x+2\right)\)
\(4x^2-20xy+25y^2=\left(2x\right)^2-2.2x.5y+\left(5y\right)^2=\left(2x-5y\right)^2\)
\(x^2+3x-x-3=x\left(x+3\right)-\left(x+3\right)=\left(x-1\right)\left(x+3\right)\)
\(x^2-xy+x-y=x\left(x-y\right)+\left(x-y\right)=\left(x-y\right)\left(x+1\right)\)
\(2y\left(x+2\right)-3x-6=2y\left(x+2\right)-3\left(x+2\right)=\left(x+2\right)\left(2y-3\right)\)
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tính = 1 cách hợp lí
a,-136+123+(-264)+(-83)+240
b,-596+2001+1999+(-404)+189
làm ơn mình đg cần gấp!
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a,-136+123+(-264)+(-83)+240
= (123 - 83) - (136 + 264) + 240
= -40 - 400 + 240
= (240 - 40) - 400
= 200 - 400 = -200
b,-596+2001+1999+(-404)+189
= (2001 + 1999) - (596 + 404) + 189
= 4000 - 1000 + 189
= 3000 + 189
= 3189
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\(2021\left(2020+2022\right)-2020\left(2021+2022\right)\\ =2021.2020+2021.2022-2020.2021-2020.2022\\ =\left(2021.2020-2020.2021\right)+\left(2021.2022-2020.2022\right)\\ =0+2022.\left(2021-2020\right)\\ =0+2022.1=2022\)