Mk gợi ý nha phần còn lại bạn làm nốt nhá

\(a,\sqrt{2x-1}-\sqrt{3}=\sqrt{x^2+2x-5}-\sqrt{3}\)

\(\Leftrightarrow\frac{2x-4}{\sqrt{2x-1}+\sqrt{3}}=\frac{\left(x-2\right)\left(x+4\right)}{\sqrt{x^2+2x-5}+\sqrt{3}}\)

\(\Leftrightarrow\left(x-2\right)\left(\frac{2}{\sqrt{2x-1}+\sqrt{3}}-\frac{x+4}{\sqrt{x^2+2x-5}+\sqrt{3}}\right)=0\)

\(b,\sqrt{x\left(x^3-3x+1\right)}=\sqrt{x\left(x^3-x\right)}\)

\(\Leftrightarrow\sqrt{x}\left(\sqrt{x^3-3x+1}-\sqrt{x^3-x}\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x^3-3x+1=x^3-x\end{cases}}\)

Câu f sai đề thì phải 

\(\sqrt{x\left(x-1\right)}+\sqrt{x\left(2x-1\right)}=x\)

\(\sqrt{x}\left(\sqrt{x-1}+\sqrt{2x-1}-\sqrt{x}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\\sqrt{x-1}+\frac{2x-2}{\sqrt{2x-1}+1}+\frac{x-1}{1+\sqrt{x}}=0\end{cases}}\)

Câu g bình lên sau đó chuyển vế và bình lên 1 lần nữa

\(h,pt\Leftrightarrow\sqrt{2x-3}+6-\sqrt{4x+3}-9=0\)

Liên hợp nha bạn

Có mấy câu mk ko bít làm mong bạn thông cảm

\(\left(\sqrt{x}+\sqrt{y}\right)\left(\frac{x\sqrt{y}-y\sqrt{x}}{\sqrt{xy}}\right)\)

\(=\left(\sqrt{x}+\sqrt{y}\right).\frac{x\sqrt{y}-y\sqrt{x}}{\sqrt{xy}}\)

\(=\frac{-y+\sqrt{x}.\sqrt{y}}{\sqrt{y}}.\left(\sqrt{x}+\sqrt{y}\right)\)

\(=\frac{\left(\sqrt{x}.\sqrt{y}-y\right)\left(\sqrt{x}+\sqrt{y}\right)}{\sqrt{y}}\)

\(=\frac{xy-y^2}{y}\)

\(=\frac{y\left(x-y\right)}{y}\)

= x - y (đpcm)

\(A=\frac{\sqrt{x}+3}{\sqrt{x}\left(\sqrt{x}+1\right)}-\frac{\sqrt{x}-3}{\sqrt{x}\left(\sqrt{x}-1\right)}\)

\(A=\frac{\left(\sqrt{x}+3\right)\left(\sqrt{x}-1\right)}{\sqrt{x}\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}-\frac{\left(\sqrt{x}-3\right)\left(\sqrt{x}+1\right)}{\sqrt{x}\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}\)

\(A=\frac{\left(\sqrt{x}+3\right)\left(\sqrt{x}-1\right)-\left(\sqrt{x}-3\right)\left(\sqrt{x}+1\right)}{\sqrt{x}\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}\)

\(A=\frac{4\sqrt{x}}{\sqrt{x}\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}\)

\(A=\frac{4\sqrt{x}}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}\)

\(A=\frac{4}{x-1}\)

b) \(\frac{4}{x-1}=7\)

\(\Leftrightarrow4=7.\left(x-1\right)\)

\(\Leftrightarrow\frac{4}{7}=x-1\)

\(\Leftrightarrow\frac{4}{7}+1=x\)

\(\Leftrightarrow\frac{11}{7}=x\)

\(\Rightarrow x=\frac{11}{7}\)