(62 +72 +82+92+102) - (12 +22 +32+42+52)
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a) \(\left(\dfrac{1}{4}\right)^3.\left(\dfrac{1}{8}\right)^2=\left(\dfrac{1}{2}\right)^6.\left(\dfrac{1}{2}\right)^6=\left(\dfrac{1}{2}\right)^{12}\)
b) \(4^2.32:2^3=2^4.4.8:2^3=2^4.2^2.2^3:2^3=2^6\)
c) \(5^2.5^3.\dfrac{1}{5^4}.5^3\)\(=5^5.\dfrac{1}{5^4}.5^3=\dfrac{5^5}{5^4}.5^3=5.5^3=5^4\)
d) \(5^6.\dfrac{1}{20}.2^2.3^3:125=5^6.\dfrac{1}{5}.\dfrac{1}{4}.2^2.3^3:5^3\)\(=\dfrac{5^6}{5}.\dfrac{2^2}{4}.3^3:5^3=5^5.3^3:5^3=5^2.3^3\)
\(a,225:15+3\left(2x+1\right)=270\\ 15+3\left(2x+1\right)=225:270\\ 15+3\left(2x+1\right)=\dfrac{5}{6}\\ 3\left(2x+1\right)=\dfrac{5}{6}:3\\ 2x+1=\dfrac{5}{18}\\ 2x=\dfrac{5}{18}-1\\ 2x=\dfrac{5-18}{18}\\ 2x=-\dfrac{13}{18}\\ x=\left(-\dfrac{13}{18}\right):2\\ x=-\dfrac{13}{36}\)
\(b,19.3-9\left(x-2\right)=0\\ 57-9\left(x-2\right)=0\\ 9\left(x-2\right)=57\\ x-2=57:9\\ x-2=\dfrac{19}{3}\\ x=\dfrac{19}{3}+2\\ x=\dfrac{19+6}{3}\\ x=\dfrac{25}{3}\)
(62 +72 +82+92+102) - (12 +22 +32+42+52)=
(62 -12 ) +(72 - 22 )+( 82 - 32 )+( 92 - 42 )+(102 - 52 )=
(6 -1) x(6+1)+(7 - 2 )(7+2)+( 8 - 3 )(8+3)+( 9 - 4)(9+4)+(10 - 5 )(10+5)
= 5 (7+9+11+13+15)=5x55=275
=36+49+64+81+100-1-4-9-16-25
=275