Chiều rộng của HCN là

17/9 - 1/3 = 14/9 (m)

Chu vi HCN là:

(17/9 + 14/9) x 2 = 62/9 (m)

S hình chữ nhật là:  

17/9 x 14/9 = 238/81 (m²)

Đ/S : C = 62/9 m ; S= 238/81 m²

Chiều rộng hình chữ nhật:

17/9 - 1/3 = 14/9 (m)

Chu vi hình chữ nhật:

(17/9 + 14/9) × 2 = 62/9 (m)

Diện tích hình chữ nhật:

17/9 × 14/9 = 238/81 (m²)

TK

1/2+5/6+11/12+19/20+29/30+41/42+55/56+71/72+89/90
1-1/2+1-1/6+1-1/12+1-1/20+1-1/30+1-1/42+1-1/56+1-1/72+1-1/90
9 – (1/2+1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90)
9 – [1/(1x2)+1/(2x3)+1/(3x4)+1/(4x5)+1/(5x6)+1/(6x7)+1/(7x8)+1/(8x9)+1/(9x10)] 
9 – ( 1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10) 
9 – (1 – 1/10) = 9 – 9/10 = 81/10

A = \(\dfrac{1}{2}\) + \(\dfrac{5}{6}\) + \(\dfrac{11}{12}\) + \(\dfrac{19}{20}\) + \(\dfrac{29}{30}\) + \(\dfrac{41}{42}\) + \(\dfrac{55}{56}\)

A = 1 - \(\dfrac{1}{2}\) + 1 - \(\dfrac{5}{6}\) + 1 - \(\dfrac{1}{12}\) + 1 - \(\dfrac{1}{20}\) + 1 - \(\dfrac{1}{30}\) + 1 - \(\dfrac{1}{42}\) + 1 - \(\dfrac{1}{56}\)

A  1 x 7 - (\(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{56}\))

^{A = 7- (\(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}\))}

^{A = 7 - (1 - \(\dfrac{1}{8}\)})

A = 7 - \(\dfrac{7}{8}\)

A = \(\dfrac{49}{8}\)

45/60 = (45 : 15)/(60 : 15) = 3/4

9/30 = (9 : 3)/(30 : 3) = 3/10

21/42 = (21 : 21)/(42 : 21) = 1/2

\(6:\dfrac{4}{6}=6\cdot\dfrac{6}{4}=\dfrac{6\cdot6}{4}=\dfrac{36}{4}=9\)

a) = 6240,339286

b) = 165,0943396

a) = 6240,339286

b) = 165,0943396

Lời giải:

Theo bài ra ta có:

$\frac{43-m}{36}=\frac{5}{12}$

$43-m=\frac{5}{12}\times 36=15$

$m=43-15$

$m=28$
Vậy số cần tìm là $28$.

275 277 279 281

bn hỏi j?

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