tìm x
a) -x/4=-9/x b) x/4=18/x+1
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=> x + x - 1 + x -2 =2
=> 3x - 3 = 2
=> 3x = 2 +3
=> 3x = 5
=> x = 5/3
\(3x-5=-7-13\)
\(\Rightarrow3x-5=-20\)
\(\Rightarrow3x=(-20)+5\)
\(\Rightarrow3x=-15\)
\(\Rightarrow x=-5\)
A) -a+(-b)=27+16=43
B) a-b=-43
C) -a.(-b)=432
D) \(\frac{a}{3}\)+\(\frac{-b}{4}\)=-9+4=-5
a) \(\frac{x}{4}=\frac{21}{28}\Rightarrow\frac{x}{4}=\frac{3}{4}\Rightarrow x=3\)
Vậy x = 3
b) \(\frac{2x}{5}=\frac{-24}{10}\Rightarrow\frac{2x}{5}=\frac{-12}{5}\Rightarrow2x=-12\Rightarrow x=-6\)
Vậy x = -6
\(a)\frac{x}{4}=\frac{21}{28}\)
\(\Rightarrow x\cdot28=4\cdot21\)
\(\Rightarrow x\cdot28=84\)
\(\Rightarrow x=3\)
\(b)\frac{2x}{5}=\frac{-24}{10}\)
Rút gọn : \(\frac{2x}{5}=\frac{-12}{5}\)
\(\Rightarrow2x=-12\)
\(\Rightarrow x=(-12)\div2=-6\)
\(\frac{1}{7}+\frac{1}{91}+\frac{1}{247}+\frac{1}{475}+\frac{1}{775}+\frac{1}{1147}\)
\(=\frac{1}{1\cdot7}+\frac{1}{7\cdot13}+\frac{1}{13\cdot19}+...+\frac{1}{31\cdot37}\)
\(=\frac{1}{6}\left(\frac{6}{1\cdot7}+\frac{6}{7\cdot13}+\frac{6}{13\cdot19}+...+\frac{6}{31\cdot37}\right)\)
\(=\frac{1}{6}\left(1-\frac{1}{7}+\frac{1}{7}-\frac{1}{13}+\frac{1}{13}-\frac{1}{19}+...-\frac{1}{31}-\frac{1}{37}\right)\)
\(=\frac{1}{6}\left(1-\frac{1}{37}\right)\)
\(=\frac{1}{6}\cdot\frac{36}{37}=\frac{6}{37}\)
Tổng cần tính bằng:\(\frac{1}{1.7}\)+\(\frac{1}{7.13}\)+\(\frac{1}{13.19}\)+\(\frac{1}{19.25}\)+\(\frac{1}{25.31}\)+\(\frac{1}{31.37}\)=(\(\frac{1}{1}\)-\(\frac{1}{7}\)+\(\frac{1}{7}\)-\(\frac{1}{13}\)+...+\(\frac{1}{31}\)\(\frac{1}{37}\)):3 =(\(1\)-\(\frac{1}{37}\)):3=\(\frac{12}{37}\)
a, -x/4 = -9/x
=> -x.x = 4.(-9)
=> -x2 = -36
=> x2 = 36
=> x = + 4
vậy_
b, x/4 = 18/x + 1
=> x(x + 1) = 4.18
=> x(x + 1) = 72
=> x(x + 1) = 8.9
=> x = 8
vậy_
a)\(\frac{-x}{4}=\frac{-9}{x}\)
\(\Rightarrow-x\times x=-9\times4\)
\(\Rightarrow-x^2=-36\)
\(\Rightarrow x=6\)