Tính D, biết:
D = 1 + 22 + 24 + 26 + ... + 22020
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ko ghi lại đề bài
x(49-3.16)=5
x(49-48)=5
x.1=5
x=5:1
x=5
chú ý: DẤU . là dấu nhân
#chúc bạn hok tốt
\(2A=2+2^2+2^3+...+2^{2020}\)
\(2A-A=\left(2+2^2+2^3+...+2^{2020}\right)-\left(1+2+2^2+2^3+...+2^{2019}\right)\)
\(\Rightarrow A=1-2^{2020}\)
2A=2+22+23+...+22020
2A-A=\left(2+2^2+2^3+...+2^{2020}\right)-\left(1+2+2^2+2^3+...+2^{2019}\right)2A−A=(2+22+23+...+22020)−(1+2+22+23+...+22019)
\Rightarrow A=1-2^{2020}⇒A=1−22020
\(\left(2x+3\right)^4=x^4\)
\(\Rightarrow2x+3=x\)
\(\Rightarrow2x-x=-3\)
\(\Rightarrow x\left(2-1\right)=-3\)
\(\Rightarrow x\cdot1=-3\)
\(\Rightarrow x=-3\)
\(=>\)\(D=2^0+2^2+2^4+...+2^{2020}\)
\(=>\)\(2^2D=2^2+2^4+2^6+...+2^{2022}\)
\(=>\)\(4D-D=\left(2^2+2^4+2^6+...+2^{2022}\right)-\left(2^0+2^2+2^4+...+2^{2020}\right)\)
\(=>\)\(3D=2^{2022}-1\)
\(=>\)\(D=\frac{2^{2022}-1}{3}\)
=>=>D=2^0+2^2+2^4+...+2^{2020}D=20+22+24+...+22020
=>=>2^2D=2^2+2^4+2^6+...+2^{2022}22D=22+24+26+...+22022
=>=>4D-D=\left(2^2+2^4+2^6+...+2^{2022}\right)-\left(2^0+2^2+2^4+...+2^{2020}\right)4D−D=(22+24+26+...+22022)−(20+22+24+...+22020)
=>=>3D=2^{2022}-13D=22022−1
=>=>D=\frac{2^{2022}-1}{3}D=322022−1