H=5/28 + 5/70 + 5/130 + .... + 5/700
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22/25.(9/11-3/2)+4/1
= 22/25 . ( -15/22) + 4/1
= -3.5 + 4/1
= 17/5
Ta có: \(A=\dfrac{3}{1x4}+\dfrac{3}{4x7}+\dfrac{3}{7x10}+...+\dfrac{3}{100x103}\)
\(=\dfrac{1}{1}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+...+\dfrac{1}{100}-\dfrac{1}{103}\)
\(=1-\dfrac{1}{103}=\dfrac{102}{103}\)
Vậy \(\dfrac{102}{103}\)
`C=(4-1)/(1xx4)+(7-4)/(4xx7)+(10-7)/(7xx10)+....+(103-100)/(100x103)`
`=(4)/(1xx4)-(1)/(1xx4)+(7)/(4xx7)-(4)/(4xx7)+(10)/(7xx10)-(7)/(7xx10)+....+(103)/(100xx103)-(100)/(100xx103)`
`=(1)/(1)-(1)/(4)+(1)/(4)-(1)/(7)+(1)/(7)-(1)/(10)+...+(1)/(100)-(1)/(103)`
`=1-(1)/(103)=(102)/(103)`
`25 xx 15 + 47 xx 95 + 25 xx 38 - 47 xx 70`
`= [ 25 xx ( 15 + 38)] + [ 47 xx ( 95 - 70)]`
`= [25 xx 53]+ [ 47 xx 25]`
`=25 xx 53 + 47xx 25`
`=25 xx ( 53 + 47)`
`=25 xx 100`
`=2500`
`#LeMichael`
27.(62+37)+73.(43+56)
= 27.99 + 73 . 99
= 99 .( 27+73)
= 99. 100
= 9900
\(B=\dfrac{2}{1\times3}+\dfrac{2}{3\times5}+\dfrac{2}{5\times7}+\dfrac{2}{7\times9}+...+\dfrac{2}{99\times101}\)
\(B=1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+....+\dfrac{1}{99}-\dfrac{1}{101}\)
\(B=1-\dfrac{1}{101}=\dfrac{100}{101}\)
\(B=\dfrac{3-1}{1x3}+\dfrac{5-3}{3x5}+\dfrac{7-5}{5x7}+\dfrac{9-7}{7x9}+...+\dfrac{101-99}{99x101}\\ =\dfrac{3}{1x3}-\dfrac{1}{1x3}+\dfrac{5}{3x5}-\dfrac{3}{3x5}+\dfrac{7}{5x7}-\dfrac{5}{5x7}+\dfrac{9}{7x9}-\dfrac{7}{7x9}+...+\dfrac{101}{99x101}-\dfrac{99}{99x101}\\ =\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+...+\dfrac{1}{99}-\dfrac{1}{101}\\ 1-\dfrac{1}{101}=\dfrac{100}{101}\)
\(H=\dfrac{5}{4x7}+\dfrac{5}{7x10}+\dfrac{5}{10x13}+....+\dfrac{5}{25x28}\\ =>\dfrac{3}{5}xH=\dfrac{3}{4x7}+\dfrac{3}{7x10}+\dfrac{3}{10x13}+....+\dfrac{3}{25x28}\\ =>\dfrac{3}{5}xH=\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}+...+\dfrac{1}{25}-\dfrac{1}{28}=\dfrac{1}{4}-\dfrac{1}{28}=\dfrac{6}{28}=\dfrac{3}{14}\\ =>H=\dfrac{5}{14}\)
Ta có: \(H=\dfrac{5}{28}+\dfrac{5}{70}+\dfrac{5}{130}+...+\dfrac{5}{700}\)
\(H=5\left(\dfrac{1}{4x7}+\dfrac{1}{7x10}+\dfrac{1}{10x13}+...+\dfrac{1}{25x28}\right)\)
\(\Rightarrow3H=15\left(\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}+...+\dfrac{1}{25}-\dfrac{1}{28}\right)\)
\(\Rightarrow3H=15\left(\dfrac{1}{4}-\dfrac{1}{28}\right)=\dfrac{45}{14}\)
\(\Rightarrow H=\dfrac{15}{14}\)