a) \(5.2^{x+1}.2^{-2}-2^x=384\)

\(\Leftrightarrow2^x.2.\frac{5}{4}-2^x=384\)

\(\Leftrightarrow2^x.\left(\frac{5}{2}-1\right)=384\)

\(\Leftrightarrow2^x.\frac{3}{2}=384\)

\(\Leftrightarrow2^x=256\)

\(\Leftrightarrow2^x=2^8\)

\(\Leftrightarrow x=8\)

c) \(\left(x+1\right)^{x+1}=\left(x+1\right)^{x+3}\)

\(\Leftrightarrow\left(x+1\right)^{x+3}-\left(x+1\right)^{x+1}=0\)

\(\Leftrightarrow\left(x+1\right)^{x+1}\left[\left(x+1\right)^2-1\right]=0\)

\(\Leftrightarrow\orbr{\begin{cases}\left(x+1\right)^{x+1}=0\\\left(x+1\right)^2-1=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x+1=0\\\left(x+1\right)^2=1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-1\\x\in\left\{0;-2\right\}\end{cases}}}\)

Vậy \(x\in\left\{0;-1;-2\right\}\)

nhầm nha : 10⁹+ 10⁸ + 10⁷ chia hết cho 555

Ta có : 

10⁹ = 1000000000

10⁸ = 100000000

10⁷ = 10000000

=> 10⁹ + 10 ⁸ + 10 ⁷ = 1000000000 + 100000000 + 10000000 = 1110000000

=> 1110000000 : 555 = 2000000 ( không dư ) 

Vậy 10⁹ + 10 ⁸ + 10 ⁷ chia hết cho 555

~ Hok tốt ~
P/s : Cái này mik làm bừa nha , ko biết đúng hay sai đâu 

Ban tu ve hinh nha

cau a +b mik lam luon thanh 1 phan nha

a+b) : Xet \(\Delta ABMva\Delta ADM\) co

\(\hept{\begin{cases}AB=AD\left(gt\right)\\\widehat{BAM}=\widehat{DAM}\left(AM.la.tia.phan.giac\right)\\AMchung\end{cases}\Rightarrow\Delta ABM=\Delta ADM\left(c-g-c\right)}\)

=> \(\widehat{MBA}=\widehat{MDA}=90^0=>MD\perp AC\)

c) xet \(\Delta ABD\) can tai A do AB=AD(gt)

co AM la tia phan giac => AM dong thoi la duong cao va la duong trung tuyen ung voi canh B

=> AM la duong trung truc cua BD

Chuc ban hoc tot

mng ơi huhu mình cần rất gấp

mng ơi huhu mình cần rất gấp

mng ơi huhu mình cần rất gấp