Tìm x biết
x+(1/3)=2/5-(-1/3)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Xét \(\Delta ABD\)và \(\Delta HBD\)có:
\(\widehat{BAD}=\widehat{BHD}=90^o\left(gt\right)\)
BD là cạnh chung
\(\widehat{ABD}=\widehat{HBD}\)(BD là tia phân giác của \(\widehat{ABC}\))
\(\Rightarrow\Delta ABD=\Delta HBD\left(CH-GN\right)\)
1) \(\left(\frac{2}{3}x-1\right)\left(\frac{3}{4}x+\frac{1}{2}\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}\frac{2}{3}x-1=0\\\frac{3}{4}x+\frac{1}{2}=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}\frac{2}{3}x=1\\\frac{3}{4}x=-\frac{1}{2}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=-\frac{2}{3}\end{cases}}\)
\(\left(2.x+\frac{1}{3}\right)^2=\frac{16}{25}\)
\(\Leftrightarrow2.x+\frac{1}{3}=\pm\sqrt{\frac{16}{25}}\)
\(\Leftrightarrow2.x+\frac{1}{3}=\pm\frac{4}{5}\)
\(\Leftrightarrow\orbr{\begin{cases}2.x+\frac{1}{3}=\frac{4}{5}\\2.x+\frac{1}{3}=-\frac{4}{5}\end{cases}}\Leftrightarrow\orbr{\begin{cases}2.x=\frac{7}{15}\\2.x=-\frac{17}{15}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{7}{30}\\x=-\frac{17}{30}\end{cases}}\)
\(\left(2.x+\frac{1}{3}\right)^2=\frac{16}{25}\)
\(\left(2.x+\frac{1}{3}\right)^2=\left(\frac{4}{5}\right)^2\)
\(\Rightarrow\orbr{\begin{cases}2.x+\frac{1}{3}=\frac{4}{5}\\2.x+\frac{1}{3}=\frac{-4}{5}\end{cases}\Rightarrow\orbr{\begin{cases}2.x=\frac{4}{5}-\frac{1}{3}\\2.x=\frac{-4}{5}-\frac{1}{3}\end{cases}\Rightarrow}\orbr{\begin{cases}2.x=\frac{12}{15}-\frac{5}{15}\\2.x=\frac{-12}{15}-\frac{5}{15}\end{cases}\Rightarrow}\orbr{\begin{cases}2.x=\frac{7}{15}\\2.x=\frac{-17}{15}\end{cases}}}\)\(\Rightarrow\orbr{\begin{cases}x=\frac{7}{15}:2\\x=\frac{-17}{15}:2\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{7}{15}.\frac{1}{2}\\x=\frac{-17}{15}.\frac{1}{2}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{7}{30}\\x=\frac{-17}{30}\end{cases}}}\)
Vậy \(x=\frac{7}{30}\)hoặc \(x=\frac{-17}{30}\)
x+1/3= 2/5-(-1/3)
x+1/3= 2/5+1/3
x = 2/5
x+1/3=2/5-(-1/3)
x+1/3=11/15
x=11/15-1/3
x=2/5
Vậy x=2/5