(-3)14.342.32
370.(-2)2
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a) A = 5-(x-2)2 \(\le\)5
<=> x-2 = 0
<=> x=2
b) B = -lx-2l-5 \(\le\)-5
<=> x-2 = 0
<=> x=2
c)C = 3-l2y-1l-lx-2l\(\le\)3
<=>\(\hept{\begin{cases}2y-1=0\\\text{x-2 = 0 }\end{cases}}\)
<=>\(\hept{\begin{cases}y=\frac{1}{2}\\x=2\end{cases}}\)
Gọi p/s trên là S
\(\Rightarrow\) \(S=\frac{\left(42-15\right)-\left(x-15\right)}{x-15}=\frac{27}{x-15}-\frac{x-15}{x-15}=\frac{27}{x-15}-1\)
Mà \(x\in Z\)\(\Rightarrow\) \(MinS< 0\)
\(\Rightarrow\) \(\frac{27}{x-15}=-27\Rightarrow x-15=-1\Rightarrow x=14\)
Khi đó , \(MinS=\frac{42-14}{14-15}=\left(-27\right)-1=\left(-28\right)\)
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Theo đề bài ta có:
\(\frac{x}{3}=\frac{y}{4}=\frac{z}{5}\)và x + y + z = 60
Áp dụng tính chất dãy tỉ số bằng nhau:
\(\frac{x}{3}=\frac{y}{4}=\frac{z}{5}=\frac{x+y+z}{3+4+5}=\frac{60}{12}=5\)
\(=>\hept{\begin{cases}x=5\cdot3=15\\y=5\cdot4=20\\z=5\cdot5=25\end{cases}}\)
Vậy x = 15; y = 20; z = 25.
ĐẬU MỢ SÀI GÒN
\(\frac{3^{14}.3^{42}.32}{3^{70}.\left(-2\right)^2}\)
\(=\frac{3^{56}.2^5}{3^{70}.2^2}\)
\(=\frac{2^3}{3^{14}}\)