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Gọi số cần tìm la x: thuong cua x chia cho 26 la a thi x chia cho 24 duoc thuong la x+2.
Theo bài ra ta có: x:26=a dư 5 \(\Rightarrow\)x= 26a+5 (1)
x:24=a+2 du 5 \(\Rightarrow\)x= 24(a+2) + 5
suy ra: 26a+5 = 24(a+2)+5
\(\Rightarrow\)26a = 24a + 48
\(\Rightarrow\)26a - 24a = 48
\(\Rightarrow\)2a = 48
\(\Rightarrow\)a = 48 : 24 = 2
Thay a= 2 vao (1) ta duoc: x= 26*2 +5 = 57
Vay so can tim la 57
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Gọi n là thương của phép chia cho 26, ta được:
26 x n + 5 = 24 x (n+2) + 5 = 24 x n + 48 + 5
2 x n = 48
n = 48 : 2 = 24
Số cần tìm là:
26 x 24 + 5 = 629
Đáp số:629
Ai tích mình mình tích lại cho(đi mà)
4 là số dư lớn nhất trong phép chia cho 5
Gọi số cần tìm là a và b = a + 16
b chia hết cho 5 và thương tăng thêm 4
b chia hết cho 9 và thương tăng thêm 2
Lúc này 2 thương hơn kém nhau 26 + 2 = 28
9 x 5 = 45 nên 45 chia cho 9 bằng 5 và 45 chia cho 5 bằng 9
Số b là : 45 x 28 : (9 - 5) = 315
Số cần tìm là : 315 - 16 = 299
A : 8 dư 12
A : 12 dư 1
A : 8 = x dư 12
A : 12 = y dư 1
x * 8 + 12 = y * 12 + 1
x + 13 = y
( x + 13 ) * 8 + 12 = y * 12 + 1
x * 8 + 104 + 12 = y * 12 + 1
x * 12 - y x8 = 116 - 8
x * 4 = 108
x = 108 : 4
x = 27
Vậy số đó là :
27 * 8 + 5 = 221
Đáp số : 221
bài này mình thi violympic trúng rồi
kết quả bằng 221
A : 8 dư 12
A : 12 dư 1
A : 8 = x dư 12
A : 12 = y dư 1
x x 8 + 12 = y x 12 +1
x + 13 = y
( x + 13 ) x 8 +12 = y x 12 +1
x x 8 + 104 + 12 = y x 12 +1
x x 12 - y x 8 = 116 -8
x x 4 = 108
x = 108 : 4
x = 27
Vậy số đó là 27 x 8 + 5 = 221
Đáp số : 221
cho mình nha
b=a+16
b chia het cho 9 va thuong tang them 2 don vi
b chia het cho 5 va thuong tang them bon don vi
hai thuong luc nay hon kem nhau:26+(4-2)=28
9*5=45 va 45 /9=5 va 45 /5 =9
vay so b la:45/(9-5)*28=315
so a can tim la:315-16=299
Gọi a là số bị chia b là thương của phép chia a: 9 , c là thương của phép chia a: 5. ta biết số dư của phép tính a : 5 += 4
Ta có :
( b*5 +4 ) - ( c*9 +2) =0
( b*5 + 2) - ( c*9 ) = 0
26*5+2 - ( c*4) =0 ( vì c - b = 26 )
c*4 = 26 *5 +2
c * 4 =132
c= 132 : 4
c =33
Vậy số cần tìm là : 33*9+2= 299