Question

[Lâm Vũ Nhi]

Tam giác ABC cân tại C .Biet \(\dfrac{AC}{AB}\)=k( k khác 1). Phan giac CM ,AN ,BP .CMR:

a)\(\dfrac{S_{ABC}}{S_{MNP}}\)=(\(\dfrac{\sqrt{k}+1}{\sqrt{k}}\))²

b)S_{MNP< \(\dfrac{S_{ABC}}{4}\)}