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\(\dfrac{\left(-0.25\right)^{-5}\cdot9^4\left(-2\right)^{-3}-2^{-3}\cdot6^9}{2^9\cdot3^6+6^6\cdot40}\)

\(=\dfrac{2^7\cdot3^8-2^6\cdot3^9}{2^9\cdot3^6+3^6\cdot2^9\cdot5}\)

\(=\dfrac{2^6\cdot3^8\left(2-3\right)}{2^9\cdot3^6\cdot6}\)

\(=\dfrac{1}{2^3}\cdot3^2\cdot\dfrac{-1}{6}\)

\(=\dfrac{-9}{6\cdot2^3}=\dfrac{-3}{2^4}=\dfrac{-3}{16}\)

8 tháng 9 2017

a) \(\frac{8^5.\left(-5\right)^8+\left(-2\right)^5.10^9}{2^{16}.5^7+20^8}\)

\(=\frac{2^{15}.5^8+\left(-2\right)^5.10^9}{2^{16}.5^7+2.10^8}\)

\(=\frac{5-2^4.10}{2}\)

\(=5-8.10\)

\(=5-80\)

\(=-75\)

8 tháng 9 2017

a ) = -0,7499957912

b ) = -0,75

a: \(=\dfrac{9}{13}\cdot\dfrac{4}{5}=\dfrac{36}{65}\)

b: \(=\dfrac{-7}{10}:\dfrac{3}{2}=\dfrac{-7}{10}\cdot\dfrac{2}{3}=\dfrac{-14}{30}=-\dfrac{7}{15}\)

c: \(=\dfrac{7}{6}\left(3+\dfrac{1}{4}-\dfrac{1}{4}\right)=\dfrac{7}{6}\cdot3=\dfrac{7}{2}\)

3 tháng 10 2021

cho xin đáp án chi tiết điiiii

 

 

 

25 tháng 12 2021

\(\text{A=}\left(\dfrac{7}{8}-0,25\right):\left(\dfrac{5}{6}-0,75\right)^2\)

\(A=\left(\dfrac{7}{8}-\dfrac{1}{4}\right):\left(\dfrac{5}{6}-\dfrac{3}{4}\right)^2\)

\(A=\left(\dfrac{7}{8}+\dfrac{-1}{4}\right):\dfrac{1}{144}\)

\(A=\dfrac{5}{8}.144=90\)

\(\text{B=}\dfrac{3}{4}.1\dfrac{4}{9}-\left(\dfrac{-3}{4}\right)\)

\(B=\dfrac{3}{4}.\dfrac{13}{9}+\dfrac{3}{4}\)

\(B=\dfrac{13}{12}+\dfrac{3}{4}\)

\(B=\dfrac{11}{6}\)

 

 

3 tháng 10 2021

nhanh hộ mình cái

 

 

 

\(\dfrac{\left(-0.25\right)^{-5}\cdot9^4\cdot\left(-2\right)^{-3}-2^{-2}\cdot6^9}{2^9\cdot3^6+6^6\cdot40}\)

\(=\dfrac{2^7\cdot3^8-2^8\cdot3^9}{2^9\cdot3^6+2^9\cdot3^6\cdot5}\)

\(=\dfrac{2^7\cdot3^8\cdot\left(-5\right)}{2^9\cdot3^6\cdot6}\)

\(=\dfrac{1}{4}\cdot9\cdot\dfrac{-5}{6}=\dfrac{-45}{24}=\dfrac{-15}{8}\)

10 tháng 12 2022

\(=\dfrac{-11}{5}\cdot\dfrac{-9}{11}\cdot\dfrac{-5}{4}\cdot\dfrac{2}{5}+2\cdot\dfrac{1}{4}\)

\(=\dfrac{-1}{2}+\dfrac{1}{2}=0\)

21 tháng 10 2023

\(\dfrac{6}{5}\sqrt{1\dfrac{9}{16}}-\left(-\dfrac{3}{4}\right)^2:0,25\)

\(=\dfrac{6}{5}\cdot\sqrt{\dfrac{25}{16}}-\dfrac{9}{16}:0,25\)

\(=\dfrac{6}{5}\cdot\sqrt{\left(\dfrac{5}{4}\right)^2}-\dfrac{9}{16}:\dfrac{1}{4}\)

\(=\dfrac{6}{5}\cdot\dfrac{5}{4}-\dfrac{9\cdot4}{16}\)

\(=\dfrac{6}{4}-\dfrac{9}{4}\)

\(=\dfrac{6-9}{4}\)

\(=-\dfrac{3}{4}\)