6³x5²x(\(\dfrac{5}{6}\))³=5²x5³=5⁵.

Cj bé iu ở đây nè cj

30x30x30-100-30=26870.

\(\dfrac{2002\times2003+4004}{2005\times2004-4010}\\ =\dfrac{2002\times2003+2002\times2}{2005\times2004-2005\times2}\\ =\dfrac{2002\times2005}{2005\times2002}\\ =1\)

trả lời cho mình ik huhu☹

(\(\dfrac{1}{9}\))² = (\(\dfrac{1^2}{3^2}\))²= ((\(\dfrac{1}{3}\))²)²=  (\(\dfrac{1}{3}\))⁴

Người này bán được 500 000 đồng em nhé 

`@` `\text {Ans}`

`\downarrow`

a)

\(2\dfrac{3}{4}-a+\dfrac{1}{4}=1\dfrac{1}{2}\)

`\Rightarrow`\(\dfrac{11}{4}-a+\dfrac{1}{4}=\dfrac{3}{2}\)

`\Rightarrow`\(\dfrac{10}{4}-a=\dfrac{3}{2}\)

`\Rightarrow`\(a=\dfrac{10}{4}-\dfrac{3}{2}\)

`\Rightarrow`\(a=\dfrac{5}{2}-\dfrac{3}{2}\)

`\Rightarrow`\(a=\dfrac{2}{2}=1\)

Vậy, `a=1`

b)

\(3\dfrac{1}{4}-a-1\dfrac{3}{4}=\dfrac{7}{9}\)

`\Rightarrow`\(a+\dfrac{3}{2}=\dfrac{7}{9}\)

`\Rightarrow`\(a=\dfrac{7}{9}-\dfrac{3}{2}\)

`\Rightarrow`\(a=-\dfrac{13}{18}\)

Vậy, \(a=-\dfrac{13}{18}\)

c)

\(2\dfrac{5}{6}-1\dfrac{1}{2}-a=\dfrac{1}{6}\)

`\Rightarrow`\(\dfrac{4}{3}-a=\dfrac{1}{6}\)

`\Rightarrow`\(a=\dfrac{4}{3}-\dfrac{1}{6}\)

`\Rightarrow`\(a=\dfrac{7}{6}\)

Vậy, \(a=\dfrac{7}{6}\)

\(A=\dfrac{1}{1\cdot2\cdot3\cdot4}+\dfrac{1}{2\cdot3\cdot4\cdot5}+\dfrac{1}{3\cdot4\cdot5\cdot6}+....+\dfrac{1}{9\cdot10\cdot11\cdot12}\)

\(3A=\dfrac{3}{1\cdot2\cdot3\cdot4}+\dfrac{3}{2\cdot3\cdot4\cdot5}+\dfrac{3}{3\cdot4\cdot5\cdot6}+...+\dfrac{3}{9\cdot10\cdot11\cdot12}\)

\(3A=\dfrac{1}{1\cdot2\cdot3}-\dfrac{1}{2\cdot3\cdot4}+\dfrac{1}{2\cdot3\cdot4}-\dfrac{1}{3\cdot4\cdot5}+...+\dfrac{1}{9\cdot10\cdot11}-\dfrac{1}{10\cdot11\cdot12}\)\(3A=\dfrac{1}{1\cdot2\cdot3}-\dfrac{1}{10\cdot11\cdot12}\)

\(A=\dfrac{1}{2}-\dfrac{1}{440}\)

\(A=\dfrac{219}{440}\)

18¹⁰:3¹⁰=(18:3)¹⁰=6¹⁰.

18¹⁰:3¹⁰=6¹⁰