c) (𝑎𝑚)𝑛=𝑎𝑚.𝑛 (𝑚,𝑛∈ℕ)
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150 - [ 120 - ( 7 - 22 )]
= 150 - [ 120 - ( 7 - 4 )]
= 150 - ( 120 - 3 )
= 150 - 117
= 33
150-[120-(7-\(2^2\))]
=150-[120-(7-4)]
=150-(120-3)
=150-117
=33
nha
![](https://rs.olm.vn/images/avt/0.png?1311)
150 - [ 120 - ( 7 - 22 ) ]
= 150 - [ 120 - ( 7 - 4 ) ]
= 150 - ( 120 - 3 )
= 150 - 117
= 33
150-[120-(7-22)
= 150 - [120 - ( 7 - 4 ) ]
= 150 - [120 - 3 ]
= 150 - 117
= 33
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\(139,\)
a)Ta có
\(56=2^3.7\)
\(140=2^2.5.7\)
\(\Rightarrow UCLN\left(56,140\right)=2^2.7=28\)
b) Ta có :
\(24=2^3.3\)
\(84=2^2.3.7\)
\(180=2^2.5.3^2\)
\(\Rightarrow UCLN\left(24,84,180\right)=2^2.3=12\)
c)Ta có
\(60=2^2.3.5\)
\(180=2^2.5.3^2\)
\(\Rightarrow UCLN\left(60,180\right)=2^2.3.5=60\)
d) Ta có :
\(15=3.5\)
\(19=19\)
\(\Rightarrow UCLN\left(15,19\right)=1\)
#Rảnh
\(140,\)
a) Ta có :
\(16=2^4\)
\(80=2^4.5\)
\(176=2^4.11\)
\(\Rightarrow UCLN\left(16,80,176\right)=2^4=16\)
b) Ta có:
\(18=2.3^2\)
\(30=2.3.5\)
\(77=7.11\)
\(\Rightarrow UCLN\left(18,30,77\right)=2.3=6\)
#Rảnh
![](https://rs.olm.vn/images/avt/0.png?1311)